The Yucca Mountain Nuclear Waste Repository, as designated by the Nuclear Waste Policy Act amendments of 1987.
Answer:
452.2 cm
Step-by-step explanation:
A = 4πr²
A = 4 (3.14) (6)²
A = 4 (3.14) (36)
A = 452.16
A = 452.2 cm (nearest tenth)
Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.´
<h3>¿Cuántas páginas se necesitarán para almacenar 517 tarjetas? </h3>
Sabemos que cada página puede almacenar hasta 9 cartas.
Entonces queremos ver cuantos grupos de 9 cartas hay en el conjunto de 517, para ver esto tomamos el cociente entre 517 y 9.
N = 517/9 = 57.44
Y no podemos tener un numero racional, así que debemos redondear al proximo número entero, que es 58.
Esto significa que debemos tener 58 páginas de plástico para contener las 517 tarjetas.
Sí quieres aprender más sobre cocientes:
brainly.com/question/3493733
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Google helps to so try that
Answer:
A sample size of 1031 is required.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error is of:

37% of freshmen do not visit their counselors regularly.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?
A sample size of n is required.
n is found when M = 0.035. So






Rounding up:
A sample size of 1031 is required.