The two consecutive integers the square root of 117 lies between are 10 and 11.
10 squared is 100 and 11 squared is 121.
Answer:
Area of shaded region = 16π in² (D)
Step-by-step explanation:
The question is incomplete without the diagram if the circles. Find attached the diagram used in solving the question.
Area of the smaller circle = 8π in²
Area of a circle = πr²
πr² = 8π
r² =8
r = √8 = 2√2
From the diagram, there are two smaller circles in a bigger circle.
The radius of the bigger circle (R) is 2times the radius of the smaller circle (r)
R = 2r
Area of bigger circle = πR²
= π×(2r)² = π×(2×2√2)²
= π×(4√2)² = π×16×(√2)²
Area of bigger circle = π×16×2
Area of bigger circle = 32π in²
Since there are two smaller circles in a bigger circle
Area of shaded region = Area of bigger circle -2(area of smaller circles)
Area of shaded region = 32π in² - 2(8π in²)
Area of shaded region = 32π in² - 16π in²
Area of shaded region = 16π in²
The length is 2.4
1.2 times 2 to take away the both width sides
minutes 2.4 from 7.2 you get 4.8 then divide by two because it’s a rectangle it has to length side and you get 2.4
Volume =
(pi)(

(height)
$Cost = ($0.09)(3.14)(9*9)(9.5) = $217.4607
He can use:
a quarter and a dime (difference: 15)
a quarter and two nickels (difference: 20)
a dime and three nickels (difference: 5)
two dimes and a nickel (difference: 5)