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Mars2501 [29]
3 years ago
13

Find the equation for parabola Focus(3,4) Directrix y=2

Mathematics
2 answers:
masha68 [24]3 years ago
6 0

Answer: Should be x-3^2=4(y-3)

Step-by-step explanation:

sveta [45]3 years ago
4 0

Answer:

Step-by-step explanation:

we know that distance d from the focus to P should be the same to the distance from P to the directrix

(x-h)^2=4p(y-k)

we need to find the y coordinate,

x is the same from focus, 3

y=(3, (4+2)/2)=(3,3)

we find p now by subtracting the y from the focus from the y that we just found

p=4-3=1

again (x-h)^2=4p(y-k), p=1

(x-3)^2=4(1)(y-3)

(x-3)^2=4(y-3),  (x-3)^2=4y-12

simplify

4y=(x-3)^2+12

y=((x-3)^2)/4 + 3

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7 0
3 years ago
Read 2 more answers
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kirill [66]
V = (pi) * r^2 * h
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8 0
3 years ago
Solve for x.<br><br> 2(4x− 9) = 5(x − 4)
cluponka [151]

Answer:

2(4x− 9) = 5(x − 4)

=>8x- 18= 5x-20

=>8x-5x= -20+18

=>3x = -2

=>x= -2/3

8 0
3 years ago
Write an equation in slope-intercept form for each line described.
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B- Not sure if it's a line
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6 0
3 years ago
If k=9 and x=5, find the value of the expression: <br> 2k - X<br><br> Please hurry
il63 [147K]

Answer:

\huge\boxed{13}

Step-by-step explanation:

= 2k - x

Given that k = 9, x = 5

= 2(9) - 5

= 18 - 5

= 13

\rule[225]{225}{2}

Hope his helped!

<h3>~AH1807</h3>
8 0
3 years ago
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