Find the equation for parabola Focus(3,4) Directrix y=2

Mathematics

2 answers:

masha68 [24]3 years ago

6 0

Answer: Should be x-3^2=4(y-3)

Step-by-step explanation:

sveta [45]3 years ago

4 0

Answer:

Step-by-step explanation:

we know that distance d from the focus to P should be the same to the distance from P to the directrix

(x-h)^2=4p(y-k)

we need to find the y coordinate,

x is the same from focus, 3

y=(3, (4+2)/2)=(3,3)

we find p now by subtracting the y from the focus from the y that we just found

p=4-3=1

again (x-h)^2=4p(y-k), p=1

(x-3)^2=4(1)(y-3)

(x-3)^2=4(y-3), (x-3)^2=4y-12

simplify

4y=(x-3)^2+12

y=((x-3)^2)/4 + 3

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