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MArishka [77]
3 years ago
9

Hi pls help this is TIMED

Mathematics
1 answer:
alexandr1967 [171]3 years ago
3 0

What is the question you have?

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The equilateral triangles shown below are similar.
Drupady [299]

Answer:

Below in bold.

Step-by-step explanation:

The smaller one has side 2 and the corresponding side on the larger one is 5, so the answer is 2/5.

The  individual sides and perimeter are one-dimensional, so:

The ratio of their perimeters is the same 2/5.

The ratio of their areas ( which is 2 dimensional) is 2^2/5^2 = 4/25.

4 0
2 years ago
Find the sin P rounded to the nearest hundredth
Lady_Fox [76]

Answer:

SOH-CAH-TOA

\sin \left(x\right)=\frac{6}{\sqrt{49+36}} = 40.60°

SOH = SIN = OPP/HYP

SIN(Θ) = 6/\sqrt{49+36 }

Step-by-step explanation:

3 0
3 years ago
Solve for congruent triangles
Elanso [62]

Answer:

11. B.

12. C.

13. A.

14. D.

Step-by-step explanation:

for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them

for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.

for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.

for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.

8 0
3 years ago
There are 6 quarters in a jar. Jill adds 2 quarters to the jar every day. Which linear equation represents the total amount of q
MakcuM [25]
Y=2x + 6. ( because 2x is 2 quarters a day and you started with 6
8 0
4 years ago
Read 2 more answers
Which value, when placed in the box, would result in a system of equations with infinitly many solutions? Y=2x - 5 2y-4x=
Nezavi [6.7K]

Given:

The system of equations is

y=2x-5

2y-4x=?

To find:

The missing value for which the given system of equations have infinitely many solutions.

Solution:

Let the missing value be k.

We have,

y=2x-5

2y-4x=k

Taking all the terms on the left side, the given equations can be rewritten as

-2x+y+5=0

-4x+2y-k=0

The system of equations a_1x+b_1y+c_1=0 and a_2x+b_2y+c_2=0 have infinitely many solutions if

\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}

We have,

a_1=-2,b_1=1,c_1=5

a_2=-4,b_2=2,c_2=-k

Now,

\dfrac{-2}{-4}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{1}{2}=\dfrac{5}{-k}

\dfrac{1}{2}=\dfrac{5}{-k}

On cross multiplication, we get

-k=10

k=-10

Therefore, the missing value is -10.

6 0
3 years ago
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