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a_sh-v [17]
3 years ago
7

Solve the equation s+2.8=6.59

Mathematics
2 answers:
sineoko [7]3 years ago
8 0
S=3.79. subtract 2.8 from 6.59 to get s
Lelu [443]3 years ago
7 0
S=3.79 hope this helps
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0.04978706 rounded three decimal places
Crank

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That's what you want.


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4 years ago
Simplify. (2/5)^4... words to fill in minimum space
Stella [2.4K]
When you have a power to a fraction, you simply take it by the top and then by the bottm.

So, split it into two: (2)^4 and (5)^4

Solve: (2)^4=16
(5)^4=625

So the fraction is: 16/625

Check to see if it reduces: It doesn't. (Odd and even numbers that have no common multiples).

Therefore, that's the answer.
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3 years ago
Which describes a correct way to construct a scatterplot?
dem82 [27]

Answer:b

Step-by-step explanation:

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6 0
4 years ago
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Jason corporation has invested in a machine that cost $75,000, that has a useful life of fifteen years, and that has no salvage
Mice21 [21]

We can solve this problem by first calculating the annual net cash inflow. This can be solved by remembering that:

Payback period = Initial investment<span> / Annual net cash inflow</span>

<span> 6 years = $75,000 / Annual net cash inflow <span> Therefore, Annual net cash inflow = $12,500   Next, we calculate for the cost. The cost we will consider here is the depreciation value of the machine. Annual depreciation = $75,000 / 15 years = $5,000   Therefore the annual net operating income is: Annual net operating income = $12,500 - $5,000 = $7,500   Simple rate of return is calculated by: Simple rate of return = Annual net operating income / Initial investment Simple rate of return = $7,500 / <span>$75,000 = 0.1 = 10%</span></span></span>
3 0
3 years ago
Select the correct answer. What is the solution to |x − 4| ≥ 7? A. -3 ≤ x ≤ 11 B. -11 ≤ x ≤ 3 C. x ≥ 11 or x ≤ -3 D. x ≥ 3 or x
hichkok12 [17]

Answer:

C) x ≥ 11 or x ≤ -3

Explanation:

Given following: |x − 4| ≥ 7

Apply absolute rule: If |u| ≥ 0 then u ≤ -a, u ≥ a

Solving stepwise:

⇒ x - 4  ≤ -7, x - 4 ≥ 7

<u>change sides</u>

⇒ x ≤ -7 + 4, x ≥ 7 + 4

<u>add/subtract integers</u>

⇒ x ≤ -3, x ≥ 11

6 0
3 years ago
Read 2 more answers
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