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soldier1979 [14.2K]
3 years ago
15

A die is rolled 200 times with the following results.

Mathematics
2 answers:
Ivanshal [37]3 years ago
4 0
It is 0.53  hope this helps you if not my bad correct me if im wrong.
Schach [20]3 years ago
3 0
<h2>Answer:</h2>

Option: a is the correct answer.

The probability of getting a even number is:

                a.    0.47

<h2>Step-by-step explanation:</h2>

The outcome and the frequency of the outcomes are given as follows:

        Outcome        Frequency

            1                          32  

           2                         36

           3                         44

            4                          20  

            5                          30

            6                         38

The experimental probability of getting an even number is calculated as the ratio of the frequency of getting an even number to the total frequency.

i.e. The frequency of getting a even number is: 36+20+38=94

( As the even numbers on a die are : 2,4 and 6

and we add the frequency corresponding to those three outcomes)

and total frequency=200

( Since the die was rolled 200 times)

Hence, the probability is given as:

P(even\ number)=\dfrac{94}{200}\\\\\\P(even\ number)=0.47

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Answer:

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Step-by-step explanation:

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We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

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Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

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Hence, maxima occurs at x = 64.

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4 years ago
Read 2 more answers
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