There are 4 possibilities:
1) No event happens
2) event A happens, not event B
3) event B happens, not event A
4) both events happen
seeing as there is a 50% chance of either event happening, I would assume that all 4 possibilities have an equal chance of happening
so if there are 4 events, then each one is 25% likely.
So the probability if them both occurring is 25%
I think
Answer:
17 cm.
Step-by-step explanation:
Because 12 cm + 5 cm. is 17 cm.
Answer:
$0.51 = 0.51 in decimal form
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
Given the probabilities:
P(A₁)= 0.35
P(A₂)= 0.50
P(A₁∩A₂)= 0
P(BIA₁)= 0.20
P(BIA₂)= 0.05
a)
Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)
Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.
b)
Considering that
you can clear the intersection from the formula
and apply it for the given events:


c)
The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:
P(B)= (A₁∩B) + P(A₂∩B)= 0.07 + 0.025= 0.095
d)
The Bayes' theorem states that:

Then:


I hope it helps!