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3 years ago

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HELP ME FAST, IF YOU ARE RIGHT I WILL MARK BRAINLIEST!! Martha drew a triangle with angle measures 60°, 60°, and 60°, and side l

engths 6 cm, 6 cm, and 6 cm. What kind of triangle did Martha draw? A. acute, equilateral B. acute, scalene C. right, isosceles D. obtuse, scalene

2 answers:

11111nata11111 [884]3 years ago

7 0

Answer:

Equilateral triangle?

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago

3 0

Answer: the answer is c

Step-by-step explanation:

You might be interested in

First Data Corp. records indicate that in 2005, 43% of adult email users received a phishing email. A phishing email replicates

ra1l [238]

Answer:

P(x) = 45/100 = 0.45

Mean sample distribution = probability x number sampled by the survey.

Mean sample distribution = 0.45 x 800 = 360.00 to two decimal places.

Step-by-step explanation:

Convert the percentage to decimal probability.

45%. P(x) = 45/100 = 0.45

If there are ranges of probability values, we construct a probability distribution table. This is not necessary in the case of one probability value(45%)

Multiply the probability by the number adults to be surveyed on whether they have received phishing emails.

0.45 x 800 = 360.

Here, we assume that the 45% recorded by 2005 data, is still valid for the recent trends.

5 0

3 years ago

Read 2 more answers

Please help<br><br><br><br> ..........................

Alenkinab [10]

Answer:

9/2

Step-by-step explanation:

perpendicular lines have slopes that are opposite and reciprocal

the reciprocal of -2/9 is 9/2

7 0

2 years ago

g A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 13

Luden [163]

Answer:

There is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43

Step-by-step explanation:

A manufacturer of sprinkler systems designed for fire protection claims that the average activating temperature is at least 135°F.

So, Null hypothesis: $H_0:\mu \geq 135$

Alternate hypothesis : $H_a:\mu$

To test this claim, you randomly select a sample of 32 systems and find the mean activation temperature to be 133°F.

x=133

n = 32

Population Standard deviation = $\sigma = 3.3^{\circ}F$

Formula : $z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

$z=\frac{133-135}{\frac{3.3}{\sqrt{32}}}\\\\z=-3.428$

z=-3.43

Refer the z table for p value

p value = 0.0003

$\alpha = 0.10$

p value < α

So, we failed to accept null hypothesis

Hence there is enough evidence to reject the manufacturer’s claim and the standardized test statistic z is -3.43

6 0

3 years ago

The NCAA is interested in estimating the difference in mean number of daily training hours for men and women athletes on college

hammer [34]

Answer:

$s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125$

$s_p =\sqrt{0.125}=0.354$

$(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032$

$(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Data given

$\bar X_M = 2.7$ represent the sample mean for men

$\bar X_F = 2.4$ represent the sample mean for women

$s_M = 0.3$ represent the sample deviation for men

$s_F = 0.4$ represent the sample deviation for women

$n_M = 10$ sample size of male

$n_F =10$ sample size of women

The confidence interval is given by:

$(\bar X_M -\bar X_F) \pm t_{\alpha/2} S_p \sqrt{\frac{1}{n_M}+\frac{1}{n_F}}$ (1)

The polled variance can be calculated with this formula:

$s^2_p = \frac{9*0.3^2 +9*0.4^2}{10+10-2}=0.125$

$s_p =\sqrt{0.125}=0.354$

For a confidence of 95% the value for the significance is $\alpha=1-0.95=0.05$ and $\alpha/2 = 0.025$ , the degrees of freedom are given by:

$df = n_M + n_F -2= 10+10-2=18$

And the critical value can be calculated with the following formula in excel: "=T.INV(1-0.025,18)" and we got $t_{\alpha/2}=2.1$

Now we can replace into the confidence interval:

$(2.7 -2.4) - 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=-0.032$

$(2.7 -2.4)+ 2.1*0.354\sqrt{\frac{1}{10}+\frac{1}{10}}=0.632$

6 0

3 years ago

Which graph represents the function f(x)=3x-2/x-2

Marta_Voda [28]

ANSWER

The last graph is the correct answer

EXPLANATION

The function,
$y = \frac{3x - 2}{x - 2}$ is a rational function.

This rational function has a vertical asymptote

at where the denominator is zero.

That is,
$x - 2 = 0$

This means that, the vertical asymptote occurs at

$x = 2$

The graph also has a horizontal asymptote at,

$y = \frac{3}{1}$

Thus, the horizontal asymptote occurs at
$y = 3$

At x-intercept,
$f(x) = 0$

This implies that,

$\frac{3x - 2}{x - 2} = 0$

$\Rightarrow \: 3x - 2 = 0$

$3x = 2$

$\Rightarrow \: x = \frac{2}{3}$

The graph cuts the x-axis at,

$( \frac{2}{3} ,0)$

At y-intercept,

$x = 0$

This implies that,

$f(0) = \frac{3(0) - 2}{0 - 2} = \frac{ - 2}{ - 2} = 1$

The graph cuts the y-axis at,

$(0,1)$

The graph that satisfy all the above conditions is the last one.

3 0

3 years ago

Read 2 more answers