A kilogram of silver contains 5.58×10²⁴ atoms.
<h3>How to determine the parameter</h3>
From the question given above, the following data were obtained:
- 1 mole of silver = 107.9 g
- Number of atoms in 1 mole of silver = 6.02×10²³ atoms.
- Number of atoms in a kilogram of silver is unknown
Now, we shall convert 1 kg of silver to grams (g).
This can be obtained as follow:
1 kg = 1000g
Therefore, 1 kg of silver is equivalent to 1000g.
Now, let's determine the number of atoms in 1 kg (i.e 1000 g) of silver as follow:
If 107.9 g of silver contains 6.02×10²³ atoms.
Then, 1000 g of silver will contain:
= (1000 × 6.02×10²³) / 107.9
= 5.58×10²⁴ atoms.
Thus, a kilogram of silver contains 5.58×10²⁴ atoms.
Learn more about atoms here:
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Answer:I=0.14*1000
I=140
Step-by-step explanation:
V= 1/3 times pi times radius squared times height
V= 1/3 • 3.14 • 4.5 squared • 4(4.5 because 9 divided by 2)
V= 1/3 • 3.14 • 20.25 • 4
V= 1.0466 • 81
V= 84.7746 units cubed
If told to round to nearest tenth then 84.8 , if hundreds then 84.78
The answer is 12.5 pounds so yes 100 ounces is more
