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I am Lyosha [343]
4 years ago
11

Find f (-3) if f(x) = x^2

Mathematics
1 answer:
xz_007 [3.2K]4 years ago
8 0

Konichiwa~! My name is Zalgo and I am here to help you out today. If f were to equal -3, first we need to put -3 into the equation. It would look like "f(-3)=x^2". The answer to that equation is 9.

I hope that this helps! :T

"Stay Brainly and stay proud!" - Zalgo

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3 years ago
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Graph the inequality.<br> 2x+5y&gt; -15
Sedbober [7]

Answer: See attached

Step-by-step explanation:

   [] Since the inequality uses greater than (>) and <em>not</em> greater than or equal to (≥), the line will be dashed.

   [] The inequality is greater than (>) so we will shade above the line as values "above" are greater.

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Solve when G= -4/3 and h= 1/3 G+2h-3g-4h
Alexandra [31]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
0.8 is 20% of what number?
Rom4ik [11]

0.8 is 20% of 4. This is because 20% of something occurs when something is divided by 5, since it is 1/5 of 100. You multiply 0.8*5, and you get 4.

6 0
4 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
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