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Sonbull [250]
4 years ago
10

Della bought a tree seedling that was 2 1/4 feet tall. During the first year, it grew 1 1/6 Feet. After two years, it was 5 feet

tall. How much did the seedling grow during the second year?
Mathematics
1 answer:
Margarita [4]4 years ago
3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Della bought a tree seeding that was 2\frac{1}{4} feet tall means \frac{9}{4} feet.

First year it grew 1\frac{1}{6} feet means it grew \frac{7}{6} feet.

It means after 1 year, the height of tree will be = \frac{9}{4}+\frac{7}{6}=\frac{41}{12}

After 2 years, the height of tree is = 5 feet

So, it grew in second year = 5-\frac{41}{12}

So, it grew in second year = \frac{60-41}{12}=\frac{19}{12}

So, it grew in second year=1\frac{7}{12} feet.   :  Answer

Hope it will help :)

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Answer:

C. (3x2 - 10) (x - 2)

Step-by-step explanation:

3x^2 - 16x +20

Step 1: Sum = - 16x

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Step 2: Find 2 numbers that their sum is -16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and -6

Step 3: Replace -16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20

Step 4: Factorise the equation in step 3, like so;

(3x^2 - 6x)(- 10x + 20)

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To check if the answer is correct, expand the bracket: (3x - 10)(x - 2)

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Step-by-step explanation:

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