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3 years ago

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Della bought a tree seedling that was 2 1/4 feet tall. During the first year, it grew 1 1/6 Feet. After two years, it was 5 feet

tall. How much did the seedling grow during the second year?

1 answer:

Margarita [4]3 years ago

3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Della bought a tree seeding that was $2\frac{1}{4}$ feet tall means $\frac{9}{4}$ feet.

First year it grew $1\frac{1}{6}$ feet means it grew $\frac{7}{6}$ feet.

It means after 1 year, the height of tree will be = $\frac{9}{4}+\frac{7}{6}=\frac{41}{12}$

After 2 years, the height of tree is = 5 feet

So, it grew in second year = $5-\frac{41}{12}$

So, it grew in second year = $\frac{60-41}{12}=\frac{19}{12}$

So, it grew in second year= $1\frac{7}{12}$ feet. : Answer

Hope it will help :)

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An industrial expert claims that the average useful lifetime of a typical car transimssion which comes with ten years warranty i

lesya692 [45]

Answer:

a. none of these answers

Data provides sufficient evidence, at 1% significance level, to support the expert's claim. In addition the p-value (or the observed significance level) is equal to P( T >3.281)

Step-by-step explanation:

Data given and notation

$\bar X=13.5$ represent the mean height for the sample

$s=3.2$ represent the sample standard deviation for the sample

$n=9$ sample size

$\mu_o =10$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 10 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 10$

Alternative hypothesis: $\mu > 10$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{13.5-10}{\frac{3.2}{\sqrt{9}}}=3.28$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=9-1=8$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(8)}>3.281)=0.00558$

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can't conclude that we have a mean higher than 10 years at 1% of significance.

a. none of these answers

3 0

3 years ago

3) x2+ y2 - x + 3y - 42 = 0<br> X+y=4

REY [17]

The solution is $(-1,5)$ and $(7,-3)$

Step-by-step explanation:

The expression is $x^{2} +y^{2} -x+3y-42=0$ and $x+y=4$

Using substitution method we can solve the expression.

Let us substitute $x=4-y$ in $x^{2} +y^{2} -x+3y-42=0$

$(4-y)^{2} +y^{2} -(4-y)+3y-42=0$

Expanding and simplifying the expression, we get,

$\begin{array}{r}{16-8 y+y^{2}+y^{2}-4+y+3 y-42=0} \\{2 y^{2}-4 y-30=0}\end{array}$

Let us use the quadratic equation formula to solve this equation,

$\begin{aligned}y &=\frac{4 \pm \sqrt{16-4(2)(-30)}}{2(2)} \\&=\frac{4 \pm \sqrt{16+240}}{4} \\&=\frac{4 \pm 16}{4} \\y &=1 \pm 4\end{aligned}$

Thus, $y=5$ and $y=-3$

Substituting y-values in the equation $x+y=4$ , we get the value of x.

For $y=5$ ⇒ $x=4-5=-1$

For $y=-3$ ⇒ $x=4+3=7$

Thus, the solution set is $(-1,5)$ and $(7,-3)$

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3 years ago

Write the phrase as an expression. Then simplify the expression. 7 plus sum of a number x and 5

jeka57 [31]

7+(x+5) would be the answer because sum means addition and it says x and 5. then it says 7 plus that so you put 7. In reality you wouldn't need parenthesis, but if you want it to match the phrase, you can put it in parenthesis.

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True or False?<br>The ratios 4/5 and 52/60 are proportional<br><br><br><br>

ZanzabumX [31]

Answer:

False

Step-by-step explanation:

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Plz help best answer gets brainly

lorasvet [3.4K]

Round up to 1, 400 then times it by 5

1,400 • 5 = 7,000

So no, it it's not reasonable.

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3 years ago