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ozzi
3 years ago
10

Suppose it is known that for a given differentiable function y=f(x), its tangent line (local linearization) at the point where a

=−4 is given by T(x)=5−7(x+4). What must be the values of f(−4) and f′(−4)?
Mathematics
1 answer:
AleksandrR [38]3 years ago
6 0

Answer:

y(-4) = 5

y'(-4) = -7

Step-by-step explanation:

Hi!

Since the tangent line T and the curve y must coincide at x=-4

y(-4) = T(-4) = 5

On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7

That is:

y'(-4) = -7

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