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2 years ago

Consider the relationships labeled in the diagram. Q Á P Р R Find m

Mathematics

1 answer:

Leni [432]2 years ago

4 0

Angle m = 60° because if all sides are congruent then all angles are congruent. a triangle’s angles add up to 180 so each angle equals 60°

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S=(1 r)<br> c. find c if s = r 174 and r= 45%

stepladder [879]

The question is incorrect because of the apparent contradiction the question makes.
First statement says that a quantity S is equal to quantity r.
The second statement says that S = 174r.
Moreover, the quantity C is not correctly linked with the equation. Please either correct the question or explain the ambiguity.

4 0

2 years ago

-12 + 2a = -6(1 + a) + 8a

valkas [14]

-12 + 2a = -6 (1+a)?
Answer is 0 = 6

8 0

1 year ago

TVs are measured by

kondor19780726 [428]

Answer:

Step-by-step explanation:

Diagonal is 60 inches, height is 24 inches so

60^2 = 24^2 + width^2

6.25 inches

4 0

2 years ago

From experience, it is known that on average 10% of welds performed by a particular welder are defective. if this welder is requ

bulgar [2K]

Binomial distribution can be used because the situation satisfies all the following conditions:1. Number of trials is known and remains constant (n)2. Each trial is Bernoulli (i.e. exactly two possible outcomes) (success/failure)3. Probability is known and remains constant throughout the trials (p)4. All trials are random and independent of the othersThe number of successes, x, is then given by $P(x)=C(n,x)p^x(1-p)^{n-x}$ where $C(n,x)=\frac{n!}{x!(n-x)!}$
Here we're given
p=0.10 [ success = defective ]
n=3

(a) x=0
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,0)0.1^0(1-0.1)^{3-0}$
$=1(1)(0.729)$
$=0.729$

(b) x=2
$P(x)=C(n,x)p^x(1-p)^{n-x}$
$=C(3,2)0.1^2(1-0.1)^{3-2}$
$=3(0.01)(0.9)$
$=0.027$

(c) x ≥ 2
$P(x)=\sum_{x=2}^3C(n,x)p^x(1-p)^{n-x}$
$=P(2)+P(3)$
$=C(n,2)p^2(1-p)^{n-2}+C(n,3)p^3(1-p)^{n-3}$
$=C(3,2)0.1^2(1-0.1)^{3-2}+C(3,3)0.1^3(1-0.1)^{3-3}$
$=3(0.01)(0.9)+1(0.001)1$
$=0.027+0.001$
$=0.028$

8 0

2 years ago

You write down the temperatures at different times on one of the match days. Time Temperature Midnight -6°C 4 am -8°C 8 am -4°C

fenix001 [56]

The highest is 7 degrees and lowest is -8 so subtract and you get a difference of 15 degrees

5 0

3 years ago

Read 2 more answers