1. x = 31
2. y = 5 + 23
3.
4. y = -7
5. x = -2 + 13
Let X be the score on an english test which is normally distributed with mean of 31.5 and standard deviation of 7.3
μ = 31.5 and σ =7.3
Here we have to find score that separates the top 59% from the bottom 41%
So basically we have to find here x value such that area above it is 59% and below it is 49%
This is same as finding z score such that probability below z score is 0.49 and above probability is 0.59
P(Z < z) = 0.49
Using excel function to find the z score for probability 0.49 we get
z = NORM.S.INV(0.49)
z = -0.025
It means for z score -0.025 area below it is 41% and above it is 59%
Now we will convert this z score into x value using given mean and standard deviation
x = (z* standard deviation) + mean
x = (-0.025 * 7.3) + 31.5
x = 31.6825 ~ 31.68
The score that separates the top 59% from the bottom 41% is 31.68
Answer:
- 12, - 7, - 2, 3, 8
Step-by-step explanation:
The general terms of an arithmetic sequence are
a, a + d, a + 2d + ....... + a + (n - 1 )d
To obtain consecutive terms in the sequence add d = 5 to the previous term
= - 12
= - 12 + 5 = - 7
= - 7 + 5 = - 2
= - 2 + 5 = 3
= 3 + 5 = 8
Answer:
g o f = 
Step-by-step explanation:
Given
Required:
Find g o f
This is calculated as:
So:
![g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4](https://tex.z-dn.net/?f=g%28f%28x%29%29%20%3D%202%5B%2016x%5E2%20%2B%2016x%20%2B%204%29%5D%20-%204)
Since there could be no more than 12 the multiples of 1/3 untill a denominator of 12 are 2/6 3/9 and 4/12
