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3 years ago

Y=3x+4 and crosses through the point (1,8)

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

3 0

The answer is your equation does not pass though the point (1,8)

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Gib Answer:

Marina86 [1]

Answer:

the probability is 1/4

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2 years ago

The regular hexagon below is centered at the origin. It is rotated clockwise around the origin through an angle of k° For which

tatiyna

Option D is correct hope i helped at all

4 0

3 years ago

Read 2 more answers

How do i solve -96=-6(1-3b) with the steps

Kay [80]

Answer:

The answer is b= - 5

Step-by-step explanation:

-96 = -6 ( 1 - 3b )

-6 ( 1 - 3b ) = -96

$\frac{-6(1 - 3b}{-6} = \frac{-96}{-6}$

1 - 3b = 16

3b = 16 - 1 = 15

b= 15 : 3 = 5

5 0

3 years ago

Emily works at a concession booth for summer sports. Hotdogs are $1.50 and sodas are $0.50. At the end of the night she made a t

pav-90 [236]

Answer:

52 sodas

Step-by-step explanation

h=hotdogs

s= sodas

1.5h+.5s=78.5

You know that Emily sold 35 hotdogs so you replace h with 35.

Therefore, 1.5(35)+.5s=78.5

52.5+.5s=78.5

.5s=26

s=52

4 0

3 years ago

Y=x2-2x-5<br> Change to vertex form

MaRussiya [10]

The vertex form is $y=(x-1)^{2} -6$

Step-by-step explanation:

The given equation $y=x^{2} -2x-5$ is a parabola. The vertex of the parabola is of the form $y=ax^{2} +bx+c$

The parameters of the parabola are $a=1, b=-2$ and $c=-5$

The vertex of the x-coordinate is given by $x=\frac{-b}{2a}$

Thus, substituting the values of a and b in $x=\frac{-b}{2a}$ , we get,

$\begin{aligned}x &=\frac{-(-2)}{2(1)} \\&=\frac{2}{2} \\x &=1\end{aligned}$

Now, substituting $x=1$ in $y=x^{2} -2x-5$ , we get,

$\begin{aligned}y &=1^{2}-2(1)-5 \\&=1-2-5 \\y &=-6\end{aligned}$

Thus, the vertex is $(1,-6)$

The equation of parabola to be in vertex form is $y=a(x-h)^{2} +k$

where a is the coefficient of $x^{2}$ , h is vertex of the x-coordinate and k is the vertex of the y-coordinate.

Hence, $a=1, h=1$ and $k=-6$

Thus, substituting the values in the equation of the vertex form,

$y=1(x-1)^{2} -6\\y=(x-1)^{2} -6$

Hence, the vertex form is $y=(x-1)^{2} -6$

8 0

3 years ago