Simplify the expression. (−0.75x + 8) + (1.5x + 4.4) The simplified expression is

Assume a recent sociological report states that university students drink 5.10 alcoholic drinks per week on average, with a stan

Lerok [7]

Answer:

Mean of sampling distribution = 5.10 alcoholic drinks per week

Standard deviation of the sampling distribution = 0.11

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 5.10 alcoholic drinks per week

Standard Deviation, σ = 1.3401

Sample size, n = 150

a) Mean of sampling distribution

The best approximator for the mean of the sampling distribution is the population mean itself.

Thus, we can write:

$\mu_{\bar{x}} = \mu = 5.10$

b) Standard deviation of the sampling distribution

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{1.3401}{\sqrt{150}} = 0.11$

3 0

2 years ago

The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took these 100 customer

AlladinOne [14]

Answer:

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=100 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.326$

Now we have everything in order to replace into formula (1):

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

4 0

3 years ago

Mr.Mason takes two-thirds of his body weight and drinks that amount of gatorade in ounces per day. If Mr.Mason drinks 118 ounces

denis-greek [22]

The total weight of Mason is 177

Solution:

Given that, Mr.Mason takes two-thirds of his body weight and drinks that amount of gatorade in ounces per day

Mr.Mason drinks 118 ounces each day

Let "x" be the total weight of Mr.Mason

Therefore, we can say,

Two third of body weight = Amount of gatorade drank in ounces per day

Two third of x = 118

$\frac{2}{3} \text{ of } = 118\\\\\frac{2}{3} \times x = 118\\\\2x = 118 \times 3\\\\2x = 354\\\\x = \frac{354}{2}\\\\x = 177$

Thus total weight of Mason is 177

6 0

3 years ago

Help with math please example 1

hram777 [196]

Answer:

I'm not very sure about this one what icing in probably not going to be right but what I think is that they're not the same because look at the size difference imagine putting an adult's next to a baby that's kind of what it's like the bigger quadrilateral is also the adults while the little one is the baby what do you think about that I probably think that they're not saying

Step-by-step explanation:

sorry I gave it to you in my answer

3 0

3 years ago

Pls help me that would be great

omeli [17]

No. No. It is not linear because the slope has to be able to be plugged in to any x, y coordinates and be placed on the line.

4 0

3 years ago