(X^10y^2)^1/5a^2/5
1 answer:
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<h2>The area of a triangle is =54 square units</h2><h2>The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)
The area of a triangle is=
=
= = 54 square units
The length of AC =
=
= units
Let the perpendicular distance from B to AC be = x
According To Problem
⇔ units
Therefore the perpendicular distance from B to AC is =
We are given
We can write it as
we can see that 2y is in first two terms
and -8 is in last two terms
so, we can factor it out
now, we can see that x+4 is common in both terms
so, we can factor it out
we can see that
x+4 is one of factor of terms
so, option-B..........Answer