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erica [24]
3 years ago
8

24) 12 21 X 84 91 28

Mathematics
1 answer:
padilas [110]3 years ago
5 0

Answer:

13

Step-by-step explanation:

12×7 = 84,

so the scale ratio is 1/7

now 91×1/7

= 91/7

= 13

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Sara is collecting signatures to pu on her towns ballot. So far, she has 432 signatures. This is 36% of the number of signatures
In-s [12.5K]

Sara needs to collect 1200 signatures.

Step-by-step explanation:

Let,

x be the total number of signatures she needs to collect

Given percentage = 36%

Signature collected = 432

According of statement;

36% of x = 432

\frac{36}{100}*x=432\\

\frac{36x}{100}=432\\Multiplying\ both\ sides\ by 100\\100*\frac{36x}{100}=432*100\\36x=43200\\Dividing\ both\ sides\ by\ 36\\\frac{36x}{36}=\frac{43200}{36}\\x=1200

Sara needs to collect 1200 signatures.

Keywords: Percentage, Division

Learn more about percentages at:

  • brainly.com/question/10879401
  • brainly.com/question/10940255

#LearnwithBrainly

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10. A manufacturer wanted to know if more coupons would be redeemed if they were mailed to the
Mandarinka [93]

Using the t-distribution, it is found that the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if there is no difference, that is, the mean is of 0, hence:

H_0: \mu = 0

At the alternative hypothesis, it is tested if the mean number is greater for females, that is, the mean is greater than 0, hence:

H_1: \mu > 0

<h3>What is the test statistic?</h3>

The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the parameters are given as follows:

\overline{x} = 1.5, \mu = 0, s = 4.75, n = 50.

Hence, the test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{1.5 - 0}{\frac{4.75}{\sqrt{50}}}

t = 2.23

<h3>What is the conclusion?</h3>

Considering a <em>right-tailed test</em>, as we are testing if the mean is greater than a value, with a <em>significance level of 0.01 and 50 - 1 = 49 df</em>, the critical value is given by t^{\ast} = 2.4.

Since the test statistic is less than the critical value for the right-tailed test, the data does not provide convincing evidence that the mean number is greater when the coupons were addressed to a female.

More can be learned about the t-distribution at brainly.com/question/26454209

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2 years ago
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