Since it is a polynomial for the zero 4 you can write (x-4) for the zero -14 you can write (x+14) for the zero 5+8i since it is complex it will be accompanied with its conjugate 5-8i so you can write (x-(5+8i) and (x-(5-8i)) =(x^2-10x+89) so (x-4)(x+14)(x^2-10x+89) expanding x^4-67x^2+1450x-4984=0