What is the range of f(x) = 3x + 9?

1 answer:

8 0

There is no restriction upon the domain, the x values, and is all real numbers or (-oo,+oo)

From such it is clear that the domain also contains all real numbers.

The range of f(x) is (-oo,+oo)

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The graph below shows the solution set of which inequality ?

Anestetic [448]

Answer:

E. $|x| < 100$ .

Step-by-step explanation:

The solution of an absolute value function of the form $|x| < a$ represents the set of values of $x$ so that $-a < x < a$ . The solution must be at least $|x| < 7$ . Hence, the right choice is $|x| < 100$ .

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3 years ago

Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o

aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{4}{\sqrt{10}} = 2.08$

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

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2 years ago

HELP PLEASE ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!11111

vaieri [72.5K]

Answer:

16(0.5x - 0.75y + 2)

Step-by-step explanation:

16 x 0.5 = 8

16 x -0.75 = -12

16 x 2 = 32

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2 years ago