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Feliz [49]
3 years ago
12

What is the range of f(x) = 3x + 9?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
8 0
There is no restriction upon the domain, the x values, and is all real numbers or (-oo,+oo)

From such it is clear that the domain also contains all real numbers.

The range of f(x) is (-oo,+oo)
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If P(x) = ax 3 + bx - 3 and P(-1)-0, then the value of P(1) is:
sergey [27]

Answer:

(a) -6

Step-by-step explanation:

P(x) = ax^3 +bx - 3

  • P(-1) = -a-b-3 = 0
  • therefore a+b=-3
  • P(1) = a+b-3
  • P(1) = -3 - 3 = -6
  • (a)
7 0
3 years ago
7 times the sum of a number and 3
insens350 [35]

Answer:

Step-by-step explanation:

7x+3

3 0
4 years ago
A rectangle is 25 in. long and 13 in. wide what is the area? gives brainliest to right answer 
Serggg [28]
The area is 325 in ^2
4 0
4 years ago
Read 2 more answers
It took Samantha 324 minuets to cook an 18 pound turkey. How many minutes per pound did it take to cook the turkey
Natalka [10]
18 min per pound

324 min.  =   X
______        _____
    18                 1 pound

324 x 1 = 324       324/18= 18 pounds

Cross multiply then divide as above.



5 0
3 years ago
A sine function is transformed such that it has a single x-intercept in the interval (0,pi), a period of pi and a y-intercept of
Alex787 [66]
Just to make sure we're using the same language, I'm going to use the function form of:

y = A\sin(kx) + h

[] I would agree that k = 2, since the period is only half as long as a normal sine function. So, we so far, have y = A sin(2x) + h. We still need to find A and h.

[] The y-intercept is 3. Remember that the y-intercept happens when x = 0. So, plugging in x = 0 into our formula, we have: 3 = A sin(2*0) + h. In other words, 3 = A sin(0) + h = 0 + h = h. So, we now know that h = 3. The formula is now y = A sin(2x) + 3.

[] Finally, there is a single x-intercept. Picture what the sine function looks like right now, it is floating in the air around y = 3. We need to stretch it vertically until it just grazes the x-axis. 

If A = 1, then our sine function bounces between 2 and 4 (+/- 1 around h = 3). But that doesn't touch 0, so no good.

If A = 2, then our sine function bounces between 1 and 5 (+/- 2 around h = 3). Again, not quite touching 0 yet.

The answer should be A = 3, then our sine function bounces between 0 and 6 (+/- 3 around h = 3).

The final formula is y = 3 sin(2x) + 3.
7 0
3 years ago
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