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OverLord2011 [107]
3 years ago
6

What is t in 197sin(12t)=141

Mathematics
1 answer:
spayn [35]3 years ago
6 0

Answer:

  t ≈ 0.0664731

Step-by-step explanation:

Use the inverse sine function.

  sin(12t) = 141/197

  12t = arcsin(141/197)

  t = arcsin(141/197)/12

  t ≈ 0.0664731 . . . . . . . radians

__

This is the principal value. There are other solutions at values of t that have integer multiples of π/6 added to this. There are also solutions where any of those values is subtracted from π.

_____

In general, angles in math are assumed to be in radians, unless specified otherwise. This angle corresponds to about 3.81°. (In geometry, the usual assumption is that angles are measured in degrees.)

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Three good friends are in the same algebra class. Their scores on a recent test are three consecutive integers whose sum is 219?
Nookie1986 [14]

Answer:

Their scores are 72, 73, and 74.

Step-by-step explanation:

(x-1) + x + (x+1) = 219

3x = 219

x = 73

3 0
3 years ago
Solve for x hhhhhhhhhhhhhhhhhhhhhhhhhh
MAVERICK [17]

9514 1404 393

Answer:

  x = 5

Step-by-step explanation:

In order to obtain a solution, we must assume that the figure is a parallelogram.

Angle BED will be congruent to angle BCD. The sum of angles in triangle BED is 180°, so we have ...

  55° +51° +(14x +4)° = 180°

  14x = 70 . . . . . . divide by °, subtract 110

  x = 5 . . . . . . . . . divide by 14

5 0
3 years ago
Pilar used five reusable shopping bags on a recent purchase she made at a grocery store. Each bag decreased the amount she spent
almond37 [142]

Answer:

-25 is the correct answer

Step-by-step explanation:

hope this helps:)

7 0
3 years ago
Find set<br> A={1, 2, 6, 10}<br> B={3, 6, 9, 10, 11}<br> C = {1, 2, 4, 7, 11}
PilotLPTM [1.2K]

If <em>U</em> = {1, 2, 3, …, 12} is the universal set, and

<em>A</em> = {1, 2, 6, 10}

<em>B</em> = {3, 6, 9, 10, 11}

<em>C</em> = {1, 2, 4, 7, 11}

then

(1) <em>A</em> U <em>B</em> is the set containing all elements from <em>A</em> and <em>B</em>,

<em>A</em> U <em>B</em> = {1, 2, 3, 6, 9, 10, 11}

(2) <em>A</em> ∩ <em>B</em> is the set of elements that are contained in both <em>A</em> and <em>B</em>,

<em>A</em> ∩ <em>B</em> = {6, 10}

(3) Unfortunately, <em>A</em> ∩ <em>B</em> U <em>C</em> is somewhat ambiguous. It could mean (<em>A</em> ∩ <em>B</em>) U <em>C</em> or <em>A</em> ∩ (<em>B</em> U <em>C </em>). Then either

(<em>A</em> ∩ <em>B</em>) U <em>C</em> = {6, 10} U {1, 2, 4, 7, 11} = {1, 2, 4, 6, 7, 10, 11}

or

<em>A</em> ∩ (<em>B</em> U <em>C </em>) = {1, 2, 6, 10} ∩ {1, 2, 3, 4, 6, 7, 9, 10, 11} = {1, 2, 6, 10}

The first interpretation is probably the intended one, since that essentially reads the set operations from left to right.

(4) <em>A'</em> U <em>B</em> is the union of <em>A'</em> and <em>B</em>, where <em>A'</em> is the complement of <em>A</em>, or all elements in <em>U</em> that are not in <em>A</em>. We have

<em>A'</em> = <em>U</em> - <em>A</em> = {3, 4, 5, 7, 8, 9, 11, 12}

and so

<em>A'</em> U <em>B</em> = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12}

(5) We have

<em>A</em> U <em>C</em> = {1, 2, 4, 6, 7, 10, 11}

so that

(<em>A</em> U <em>C </em>)<em>'</em> = <em>U</em> - (<em>A</em> U <em>C</em> ) = {3, 5, 8, 9, 12}

(6) We have

<em>B'</em> = <em>U</em> - <em>B</em> = {1, 2, 4, 5, 7, 8, 12}

and so

<em>A</em> ∩ <em>B'</em> = {1, 2}

(7) Using the complements found in (4) and (6), we have

<em>A'</em> U <em>B'</em> = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

Alternatively, we can use the fact that

<em>A'</em> U <em>B'</em> = (<em>A</em> ∩ <em>B</em>)<em>'</em>

and since we know from (2) that <em>A</em> ∩ <em>B</em> = {6, 10}, we end up with the same result,

(<em>A</em> ∩ <em>B</em>)<em>'</em> = <em>U</em> - (<em>A</em> ∩ <em>B</em>) = {1, 2, 3, 4, 5, 7, 8, 9, 11, 12}

(8) We have

<em>A</em> U <em>B</em> U <em>C</em> = {1, 2, 3, 4, 6, 7, 9, 10, 11}

so that

(<em>A</em> U <em>B</em> U <em>C</em> )<em>'</em> = {5, 8, 12}

6 0
3 years ago
Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and th
blondinia [14]

Answer:

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normal distribution with a mean of 7.2 minutes and a standard deviation of 2.1 minutes.

This means that \mu = 7.2, \sigma = 2.1

Probability that the response time is between 3 and 9 minutes.

This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3. So

X = 9

Z = \frac{X - \mu}{\sigma}

Z = \frac{9 - 7.2}{2.1}

Z = 0.86

Z = 0.86 has a pvalue of 0.8051

X = 3

Z = \frac{X - \mu}{\sigma}

Z = \frac{3 - 7.2}{2.1}

Z = -2

Z = -2 has a pvalue of 0.0228

0.8051 - 0.0228 = 0.7823

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

3 0
3 years ago
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