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3 years ago

A utility (such as a power company) which controls all services in a designated area is called a

2 answers:

7 0

These are the choices I found on the internet:
<span>A) trust.
B) cartel.
C) natural monopoly.
D) devised oligopoly.

The best answer would be letter C - natural monopoly. </span>This is a situation where one firm can supply a market's entire demand (because of a unique raw material, technology, or other factors) for a good or service at a value lower than two or more firms.

Svetradugi [14.3K]3 years ago

6 0

Answer: Natural Monopoly

Step-by-step explanation: natural monopoly are firms thats produce and sell identical products.

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Answer:

Sirius will be 20 years old and his father will be 40 years old. ratio form: 20:40

Step-by-step explanation:

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3 years ago

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3 years ago

As part of his math assignment, Santos has to estimate the height

ycow [4]

Answer:

105.46 feet

Step-by-step explanation:

We know all three angles (60, 90, and 30), as well as one side, which is adjacent to the 60 degrees. We want to find the side opposite to the 60 degree angle. To do this, we can use tangent, utilizing both opposite and adjacent.

Using tan, we can say that tan(60) = x/58, with x representing the height of the lighthouse (minus 5, because Santos is 5 feet tall and he is measuring the angle from the top of his head). Multiplying both sides by 58, we can get that 58 *tan(60) = x = 100.46. Add 5 to that to get 105.46 feet as your answer.

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A circular garden at a park has a diameter of 20 feet. A contractor is developing plans to build a 5 foot-wide walkway around th

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3 years ago

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago