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julsineya [31]
4 years ago
6

The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditio

ns must be true?
a. P(B|A) = y
b. P(A|B) = y
c. P(B|A) = x
d. P(A and B) = x + y

e. P(A and B) = x/y

P(A)
Mathematics
2 answers:
zzz [600]4 years ago
5 0

If two events are independent, then

Pr(A\cap B)=Pr(A)\cdot Pr(B).

Use formulas for conditional probabilities:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)},\\ \\ Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr(A)}.

For independent events these formulas will be:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}=\dfrac{Pr(A)\cdot Pr(B)}{Pr(B)}=Pr(A),\\ \\ Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr(A)}=\dfrac{Pr(A)\cdot Pr(B)}{Pr(A)}=Pr(B).

Now in your case Pr(A)=x,\ Pr(B)=y and Pr(A|B)=x,\ Pr(B|A)=y, Pr(A\cap B)=x\cdot y.

This shows that the only correct choice is A.

Novay_Z [31]4 years ago
5 0
The right answer for the question that is being asked and shown above is that: "d. P(A and B) = x + y." The probability of event A is x, and the probability of event B is y. If the two events are independent, the condition must be true is this d. P(A and B) = x + y

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Step-by-step explanation:

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Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

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