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emmainna [20.7K]
3 years ago
9

A special 8 sided die is rolled 20 times with these outcomes: 2, 4, 7, 3, 1,5, 4, 6, 3, 8, 6, 2, 5, 2, 6, 1, 7, 4, 5, 6 What is

the experimental probability of rolling a 2 or a 4? Is this number great than or less than the theoretical probability of rolling a 2 or 4?
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0
In your data set, 2 and 4 each show up 3 times. The experimental probability of rolling a 2 or 4 is 6/20 = 0.30.

The theoretical probability of rolling one of 2 given numbers out of 8 is 2/8 = 0.25. The experimental probability in this case is greater than the theoretical probability.
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The resting heart rate for an adult horse should average about µ = 47 beats per minute with a (95% of data) range from 19 to 75
KatRina [158]

Answer:

a. 0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. 0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. 0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

Step-by-step explanation:

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean:

\mu = 47

(95% of data) range from 19 to 75 beats per minute.

This means that between 19 and 75, by the Empirical Rule, there are 4 standard deviations. So

4\sigma = 75 - 19

4\sigma = 56

\sigma = \frac{56}{4} = 14

a. What is the probability that the heart rate is less than 25 beats per minute?

This is the p-value of Z when X = 25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 47}{14}

Z = -1.57

Z = -1.57 has a p-value of 0.0582.

0.0582 = 5.82% probability that the heart rate is less than 25 beats per minute.

b. What is the probability that the heart rate is greater than 60 beats per minute?

This is 1 subtracted by the p-value of Z when X = 60. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 47}{14}

Z = 0.93

Z = 0.93 has a p-value of 0.8238.

1 - 0.8238 = 0.1762

0.1762 = 17.62% probability that the heart rate is greater than 60 beats per minute.

c. What is the probability that the heart rate is between 25 and 60 beats per minute?

This is the p-value of Z when X = 60 subtracted by the p-value of Z when X = 25. From the previous two items, we have these two p-values. So

0.8238 - 0.0582 = 0.7656

0.7656 = 76.56% probability that the heart rate is between 25 and 60 beats per minute

3 0
3 years ago
Write 3 addition facts that have the same sum as 5 + 9
Dovator [93]

Answer:

10+4=14

8+6=14

13+1=14


5 0
3 years ago
Read 2 more answers
25.7 is what percent of 141?
Lady_Fox [76]

Answer:

about 18.2%

Step-by-step explanation:

All you have to do is divide the result of the percent, so 25.7, by the total, 141.

So 25.7÷141=0.18226950354

We round it to 0.182 and multiply it by 100 to know the percent which is 18.2

7 0
4 years ago
Y + 2 = -3(x-4)<br> complete the missing value in the solution to the equation
FinnZ [79.3K]

Answer:

y = -3x +10 Step-by-step explanation:

y+2 = -3(x-4)

y+2 = (-3*x) + (-3*-4)

y+2 = -3x + 12

 ^ -2 = .      ^ -2

y = -3x +10

3 0
3 years ago
What is the solution to 3.25x + 1 − 4.25x = −2?
Dovator [93]

Answer:

x = 3

Step-by-step explanation:

7 0
3 years ago
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