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pochemuha
3 years ago
9

Jacques built a house that measured 75 feet long by 30 feet wide.

Mathematics
1 answer:
Sergio039 [100]3 years ago
4 0
The area is 2250 square feet.
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Triangle ABC has angles measuring 137°, 15°, and 28°. Classify the triangle by its angle measures.
Lemur [1.5K]

Answer:12

Step-by-step explanation:hxdhvxrjjnvcxx

3 0
3 years ago
Jessica bought a computer for $325 and had to pay 6% sales tax. What was the total cost of Jessica’s computer?
EastWind [94]
C.) 344.50

Take what she paid before tax (325) and multiply it by 1.06 (the tax rate) and there's your answer. 
5 0
3 years ago
For each part, give a relation that satisfies the condition. a. Reflexive and symmetric but not transitive b. Reflexive and tran
Vesnalui [34]

Answer:

For the set X = {a, b, c}, the following three relations satisfy the required conditions in (a), (b) and (c) respectively.

(a) R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)} is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)} is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)} is symmetric and transitive but not reflexive .

Step-by-step explanation:

Before, we go on to check these relations for the desired properties, let us define what it means for a relation to be reflexive, symmetric or transitive.

Given a relation R on a set X,

R is said to be reflexive if for every a \in X, (a,a) \in R.

R is said to be symmetric if for every (a, b) \in R, (b, a) \in R.

R is said to be transitive if (a, b) \in R and (b, c) \in R, then (a, c) \in R.

(a) Let R = {(a,a), (b,b), (c, c), (a, b), (b, a), (b, c), (c, b)}.

Reflexive: (a, a), (b, b), (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \implies (b, a) \in R

Therefore R is symmetric.

Transitive: (a, b) \in R \ and \ (b, c) \in R but but (a,c) is not in  R.

Therefore, R is not transitive.

Therefore, R is reflexive and symmetric but not transitive .

(b) R = {(a, a), (b, b), (c, c), (a, b)}

Reflexive: (a, a), (b, b) \ and \ (c, c) \in R

Therefore, R is reflexive.

Symmetric: (a, b) \in R \ but \ (b, a) \not \in R

Therefore R is not symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is reflexive and transitive but not symmetric .

(c) R = {(a,a), (a, b), (b, a)}

Reflexive: (a, a) \in R but (b, b) and (c, c) are not in R

R must contain all ordered pairs of the form (x, x) for all x in R to be considered reflexive.

Therefore, R is not reflexive.

Symmetric: (a, b) \in R and (b, a) \in R

Therefore R is symmetric.

Transitive: (a, a), (a, b) \in R and (a, b) \in R.

Therefore, R is transitive.

Therefore, R is symmetric and transitive but not reflexive .

4 0
3 years ago
What is the median of this set of data: 593, 588, 540, 434, 420, 398, 390, 375
Aleks04 [339]

<u>Answer:</u>

<u><em>426</em></u>

<u />

<u>Explanation:</u>

To find the median number in a set of data start by reordering the data from least to greatest.

<em>original data set:</em>

<em>593, 588, 540, 434, 420, 398, 390, 375</em>

<em />

<em>data set from least to greatest:</em>

<em>375, 390, 398, 420, 434, 540, 588, 593</em>

<em />

Next, you would usually just have to find the middle number in the data set and that would be your median. However, this data set has no one number that is directly in the middle. So, we will add both middle numbers together and then divide our answer by two.

<em>375, 390, 398, </em><em>420, 434</em><em>, 540, 588, 593</em>

<em />

<em>420 + 434 = 854</em>

<em />

<em>854 ÷ 2 = 426</em>

<em />

Therefore, the median of the given data set is <em><u>426.</u></em>

5 0
3 years ago
How t solve polynomials????? HELPPPP EXAM TMRW!!!!
Alecsey [184]

Answer:

B) 1296 D) 729

Step-by-step explanation:

It's pretty straight forward, just put the values into your calculator. The question is asking to evaluate instead of simplifying, so this works. If you don't have a calculator, here are some tricks. Do them step by step in your head slowly if you have to, for fractions do them alone, and then divide them. Also in D, don't let the second value of (3)3)0 scare you, any exponent with a 0 in it is automatically 1! Hope I could help.

7 0
3 years ago
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