Answer:
SE(X) = σx = 4.5
Var(X) = 20.25
Step-by-step explanation:
Solution:-
- A large population has a mean ( u ) and standard deviation ( σ ). The parameters of the population distribution are given as follows
u = 150
σ = 27
- A sample of n = 36 people were taken from the population.
- We will first estimate the sample standard deviation (σ) by assuming that the population is normally distributed with conditions :
n ≥ 30
u ≥ 10
- The condition of normality are valid. The population is assumed to be normally distributed. The sample must also be normally distributed. The sample standard deviation (σx):
σx = σ/√n = 27/√36
σx = 4.5 ... sample standard deviation.
- The sample variance can be determined by:
Var ( X ) = ( σx ) ^2
Var ( X ) = ( 4.5 ) ^2
Var ( X ) = 20.25
Answer:
68.57 mph
Step-by-step explanation:
<span>468.75
round up if asks for you to
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A) For each year that kevin has had the tree, it grew 1 foot. Therefore for every 1 year that passes, kevin’s tree grows 1 foot.
B) 5+T= H
