Average speed of Car 1 = 35 mph. Average speed of Car 2 = 55 mph. Time elapsed between start of Car 1 and start of Car 2 = 18 mi
2 answers:
Answer:
0.53
Step-by-step explanation:
Given that two cars are going in the same direction.
I car started 18 minutes before.
So initially I car would be distance travelled 18 minutes ahead of II car which is yet to start
Since speed is 35 miles per hour i.e. 35(60) miles per minute
in 18 minutes distance travelled by I car = 35(18/60) = 10.5 miles
The relative speed = difference of speeds = 55-35 = 20 mph
TO overtake car I time taken
= distance ahead by I car/relative speed
=
In hours this equals = 0.53
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Answer:
- g(20) > f(20)
- g(x) exceeds f(x) for any x > 4
Step-by-step explanation:
As with most graphing problems not involving straight lines, it works well to start with a table of values. Pick a few values of x and compute f(x) and g(x) for those values. Plot the points and draw a smooth curve through them.
As in the attached, your table will show that there are two points of intersection between f(x) and g(x), and that for values of x more than 4, g(x) becomes much greater very quickly. Both curves rapidly reach the top of your graph space.
To find whether f(20) or g(20) is greater, you can evaluate the functions for that value of x.
f(20) = 20² = 400
g(20) = 2²⁰ = 1,048,576
Clearly, g(20) has a greater value.
Answer:
everything can be found in the picture above. I hope it helps
