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4 years ago

14

Using the segment addition postulate, which is true? A number line going from negative 9 to positive 9. A closed circle appears

at negative 6 and is labeled A. A closed circle appears at negative 1 and is labeled B. A closed circle appears at positive 2 and is labeled C. A closed circle appears at positive 8 and is labeled D.

1 answer:

boyakko [2]4 years ago

4 0

Answer:

The answer is given below

Step-by-step explanation:

The addition postulate for line segment states that if we have points A, C and a point B on line AC, The distance between points A and C can be given as:

AC = AB + BC

Point A is at -6, point B is at -1, point C is at +2 and point D is at point 8.

Therefore using line segment postulates:

AD = AB + BC + CD

But AB = -1 - (-6)= -1 + 6 = 5

BC = 2- (-1) = 2 +1 = 3

CD = 8 - (+2) = 8 - 2 = 6

Also AD = 8 - (-6) = 8 + 6 = 14

To prove AD = AB + BC + CD

AD = 5 + 3 + 6 = 14

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Step-by-step explanation:

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3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Ne4ueva [31]

Answer:

Part 1) $-1.25$ -------> $2.75/(-2.2)$

Part 2) $-4\frac{1}{3}$ --------> $(-2\frac{3}{5}) / (\frac{3}{5})$

Part 3) $\frac{2}{3}$ ------> $(-\frac{10}{17}) / (-\frac{15}{17})$

Part 4) $3$ ------> $(2\frac{1}{4}) / (\frac{3}{4})$

Step-by-step explanation:

Part 1) we have

$2.75/(-2.2)$

To calculate the division problem convert the decimal number to fraction number

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so

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Remember that

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(275/100)/(-22/10)=(275/100)*(-10/22)=-(275*10)/(22*100)=-(275)/(220)$

Simplify

Divide by 22 both numerator and denominator

$-(275)/(220)=-125/100=-1.25$

Part 2) we have

$(-2\frac{3}{5}) / (\frac{3}{5})$

To calculate the division problem convert the mixed number to an improper fraction

$(-2\frac{3}{5})=-\frac{2*5+3}{5}=-\frac{13}{5}$

so

$(-\frac{13}{5}) / (\frac{3}{5})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{13}{5}) / (\frac{3}{5})=(-\frac{13}{5})*(\frac{5}{3})=-\frac{13*5}{5*3}=-\frac{13}{3}$

Convert to mixed number

$-\frac{13}{3}=-(\frac{12}{3}+\frac{1}{3})=-4\frac{1}{3}$

Part 3) we have

$(-\frac{10}{17}) / (-\frac{15}{17})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

$(-\frac{10}{17}) / (-\frac{15}{17})=(-\frac{10}{17})*(-\frac{17}{15})=\frac{10*17}{17*15}=\frac{10}{15}$

Simplify

Divide by 5 both numerator and denominator

$\frac{10}{15}=\frac{2}{3}$

Part 4) we have

$(2\frac{1}{4}) / (\frac{3}{4})$

To calculate the division problem convert the mixed number to an improper fraction

$(2\frac{1}{4})=\frac{2*4+1}{4}=\frac{9}{4}$

so

$(\frac{9}{4}) / (\frac{3}{4})$

Since division is the opposite of multiplication, you can turn this division problem into a multiplication problem by multiplying the top fraction by the reciprocal of the bottom fraction

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