For this case we have the following function:
Where,
g: number of gallons of gas
M (g): number of miles that Danny's truck travels
We know that the maximum capacity is 20 gallons of gas.
Therefore, the maximum distance the truck can travel is given by:
Thus, the domain of the function is:
The range of the function is:
Answer:
A domain and range that are reasonable for the function are:
D. D: 0 ≤ g ≤ 20
R: 0 ≤ M (g) ≤ 340
Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via
<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em> ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>
where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.
P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)
… = P(<em>Z</em> < 0.24)
… ≈ 0.5948
Answer:
The correct option is c.
Step-by-step explanation:
The quotient of the polynomials is
We need to find the remainder by using long division method.
The dividend of the given expression is
The long division method is shown below.
From the below attachment it is clear that the quotient has a remainder of 30. Therefore, the divisor is not factor of the dividend.
Therefore the correct option is c.
First, the formula for the average of a data set must be defined. It is calculated by adding all the numbers in the data set and then dividing the sum by the number of data. In this case, the average is set to be equal to $400 with the total number of data being 3, with the September expenditure set as an unknown, x. The equation is then set-up to be: 400 = (401.5 + 250 + x)/3. Thus, Joshua can spend as much as $ 548.5 to be able to have the same average as in his second quarter expenditure.
Answer:
4 x (7-x)
Step-by-step explanation:
4 times (multiply) the difference (subtraction) of 7 and a number (seeing as how you don't know that number use a variable, x)
