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alina1380 [7]
4 years ago
14

Using the segment addition postulate, which is true? A number line going from negative 9 to positive 9. A closed circle appears

at negative 6 and is labeled A. A closed circle appears at negative 1 and is labeled B. A closed circle appears at positive 2 and is labeled C. A closed circle appears at positive 8 and is labeled D.
Mathematics
1 answer:
boyakko [2]4 years ago
4 0

Answer:

The answer is given below

Step-by-step explanation:

The addition postulate for line segment states that if we have points A, C and a point B on line AC, The distance between points A and C can be given as:

AC = AB + BC

Point A is at -6, point B is at -1, point C is at +2 and point D is at point 8.

Therefore using line segment postulates:

AD = AB + BC  + CD

But AB = -1 - (-6)= -1 + 6 = 5

BC = 2- (-1) = 2 +1 = 3

CD = 8 - (+2) = 8 - 2 = 6

Also AD = 8 - (-6) = 8 + 6 = 14

To prove AD = AB + BC  + CD

AD = 5 + 3 + 6 = 14

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Answer:

The domain: all real numbers;

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Step-by-step explanation:

The domain and the range of the parent function y=x^2 are all real numbers and all real numbers that are greater or equal to 0.

Given graph of the function f(x) is translated graph of the parent function 2 units down. Thus, the domain of the function f(x) is the same as the domain of the parent function and the range is y\ge -2.

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Can someone please help me with one or both of these problems, I'm so confused but the assignment is due soon!!
Firlakuza [10]

Answer:

First question: 1270

Second question: 4080

Step-by-step explanation:

Here is the Sum formula:

S_{n}=\frac{n}{2}(a_{1}+a_{n})

where n represents the number of terms, and

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Let's look at the first question:

k is the first number of the sequence, 5, and 20 is the last number of the sequence.

You can find the first term (a_{1}) by substituting k in the formula for 5.

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You can find the last term (a_{n}) by substituting k for 20 into the formula.

3(20)+26=60+26=86

now, knowing there are 20 terms in total, a_{1} =41, and a_{n} =86, we can put it into the Sum formula.

S_{20}= \frac{20}{2} (41+86)

S_{20}= \frac{20}{2} (127)

S_{20}= 10 (127)

S_{20}= 1270

Answer to the first question: 1270

Next question:

Even though the given formula uses n as the variable, this problem works the same way as the previous one.

Substitute n in the formula for k, which is 5 to find the first term: 14(5)+29=99

Substitute 20 for n to find the second term: 14(20)+29=309

Now assemble the Sum formula:

S_{20}= \frac{20}{2} (99+309)

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