Hello,
Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3
Proof: a+b+c=15.9+5.3+31.8=53
The second number is 5.3
Answer:
-33c+22d
Step-by-step explanation:
=(−11)(3c+−2d)
=(−11)(3c)+(−11)(−2d)
M = (y2-y1)/(x2-x1)
= (4-14)/3-1
= -10/2
= -5