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Anastaziya [24]

3 years ago

6

Can someone show me the working out for this questions and not just tell me the answer please the equation is;

1 answer:

Sergeeva-Olga [200]3 years ago

6 0

Do the same thing to both sides as long as not divide by zero
PEMDAS
parenthasees
exponents (include square root)
multiplication or division
addition or subtraciton

5y/6-2y/3+5=y
interesting
isolate the variable
subtract 5 from both sides
5y/6-2y/3=y-5
subtract y from both sides
5y/6-2y/3-y=-5
try to clear fractions by multplying by greatest common multiplue of 6,3, and 1 which happens to be 6
multiply both sides by 6
5y-(2 times 2y)-6y=-30
5y-4y-6y=-30
add like terms
-5y=-30
multiply -1
5y=30
divide both sides by 5
y=6

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5. Which polynomial is equal to (x5 + 1) divided by (x + 1)?

Mkey [24]

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Step 1: First The dividend is $(x^5+1)$ and Divisor is $(x+1)$ when divided first time the quotient will be $x^4$ and remainder will be $-x^4+1$

Step: 2 Now the new dividend is $-x^4+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3$ and remainder will be $x^3+1$

Step: 3 Now the new dividend is $x^3+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2$ and remainder will be $-x^2+1$

Step: 4 Now the new dividend is $-x^2+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x$ and remainder will be $x+1$

Step: 5 Now the new dividend is $x+1$ and Divisor is $(x+1)$ when divided the quotient will be $x^4-x^3+x^2-x+1$ and remainder will be 0.

Hence When the polynomial $(x^5+1)$ is divided by $(x+1)$ the answer or quotient will be equal to $x^4-x^3+x^2-x+1$ and remainder will be 0.

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