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Anastaziya [24]
3 years ago
6

Can someone show me the working out for this questions and not just tell me the answer please the equation is;

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
Do the same thing to both sides as long as not divide by zero
PEMDAS
parenthasees
exponents (include square root)
multiplication or division
addition or subtraciton


5y/6-2y/3+5=y
interesting
isolate the variable
subtract 5 from both sides
5y/6-2y/3=y-5
subtract y from both sides
5y/6-2y/3-y=-5
try to clear fractions by multplying by greatest common multiplue of 6,3, and 1 which happens to be 6
multiply both sides by 6
5y-(2 times 2y)-6y=-30
5y-4y-6y=-30
add like terms
-5y=-30
multiply -1
5y=30
divide both sides by 5
y=6
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Does anyone know the answer to this ?
nataly862011 [7]

Answer:

ABC and MNP are not congruent. ABC and EFG are not congruent. ABC and STU are congruent. EFG and MNP are congruent. EFG and STU are not congruent. STU and MNP are not congruent.

Step-by-step explanation:


4 0
3 years ago
3x&lt;27<br> Solve for x. help....<br> problem:<br> 3x &lt; 27 x= ? and explain
valentinak56 [21]

Answer:

x could be

anywhere from 0 to 8.99999

Step-by-step explanation:

7 0
3 years ago
At a company fish fry , 1/2 were employees. 1/3 were spouses of employees. what is the percentage of the people who are not empl
qwelly [4]
Well, find a common denominator.  We have the common denominator to be 6.

So, 3/6 is employees.  2/6 is spouses of employees.  So, 1/6 is left, and that is your answer 
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3 years ago
I need help with a photo and y’all can choose whatever like for number 7
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Step-by-step explanation:

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3 0
3 years ago
Write the linearization of the function at the points indicated. (Enter your answer as an equation. Let x be the independent var
Natalija [7]

Answer:

\displaystyle y=5+\frac{x}{10}

\displaystyle y=10+\frac{(x-75)}{20}

Step-by-step explanation:

<u>Linearization</u>

It consists of finding an approximately linear function that behaves as close as possible to the original function near a specific point.

Let y=f(x) a real function and (a,f(a)) the point near which we want to find a linear approximation of f. If f'(x) exists in x=a, then the equation for the linearization of f is

y=f(x)=f(a)+f'(a)(x-a)

Let's find the linearization for the function

y=\sqrt{25+x}

at (0,5) and (75,10)

Computing f'(x)

\displaystyle f'(x)=\frac{1}{2\sqrt{25+x}}

At x=0:

\displaystyle f'(0)=\frac{1}{2\sqrt{25+0}}=\frac{1}{10}

We find f(0)

f(0)=\sqrt{25+0}=5

Thus the linearization is

\displaystyle y=f(0)+f'(0)(x-0)=5+\frac{1}{10}x

\displaystyle y=5+\frac{x}{10}

Now at x=75:

\displaystyle f'(75)=\frac{1}{2\sqrt{25+75}}=\frac{1}{20}

We find f(75)

f(75)=\sqrt{25+75}=10

Thus the linearization is

\displaystyle y=f(75)+f'(75)(x-75)=10+\frac{1}{20}(x-75)

\displaystyle y=10+\frac{(x-75)}{20}

5 0
3 years ago
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