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2 years ago

I'll give brainiest to the first person to respond BUT only if the answer is correct

Mathematics

2 answers:

jeyben [28]2 years ago

8 0

The correct answer is option E

vesna_86 [32]2 years ago

4 0

Answer:
~Senpi Boi here~

Step-by-step explanation:
The one that each point had been reflected is Option E I believe, only because both the points (7, 1) and (7, -1) kinda reflect on each other when shown on the graph.

(Hope this helps!)

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Answer:

6, 18

Step-by-step explanation:

8-2=6

24-6=18

Have a great day!

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2 years ago

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3 years ago

4x + 6y = 18 & 4x – 2y = 10

kherson [118]

Answer:

x=4.875

y=-0.25

Step-by-step explanation:

4x – 2y = 10

2x-y=10

y=2x-10

4x + 6y = 18

2x+3(2x-10)=9

8x=39

x=4.875

y=2(4.875)-10

y=-0.25

8 0

3 years ago

At midnight, the temperature was -8oF. At noon, the temperature was 23oF. Which expression represents the increase in temperatur

irinina [24]

Answer:

$23^oF-(-8^oF)$

Step-by-step explanation:

We have been given that at midnight, the temperature was $-8^oF$ . At noon, the temperature was $23^oF$ .

Since our temperature has increased to 23 degree Fahrenheit from -8 degree Fahrenheit, we can represent this increase in temperature as:

$\text{The increase in temperature}=23^oF-(-8^oF)$

Therefore, the expression $23^oF-(-8^oF)$ represents the increase in temperature.

6 0

3 years ago

Read 2 more answers

Analyze Corey’s work to find his error. What is Corey’s mistake? He substituted 80 for x instead of y. He should have added 88.2

Anni [7]

x is the temperature and y is the number of swimmers. If there are 80 swimmers, then y = 80 instead of x = 80

This is how Corey should have solved

y = 1.505*x - 88.21

80 = 1.505*x - 88.21 <--- replace y with 80

1.505*x - 88.21 = 80

1.505*x = 80 + 88.21 <--- add 88.21 to both sides

1.505*x = 168.21

x = 168.21/1.505 <--- divide both sides by 1.505

x = 111.767

x = 111.8

If there are 80 swimmers at the pool, then the possible outside temperature is roughly 111.8 degrees F. This temperature seems awfully large, so it's possible that Corey's regression equation has limited scope; in other words, it isn't too useful if x is outside a given interval

<h2> IF YOU DONOT WANT TO READ SO MUCH THEN </h2>

PLEASE SEE THE ATTACHMENT 

4 0

3 years ago