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ArbitrLikvidat [17]

3 years ago

8

A car averages 27 miles per gallon. If gas costs $4.04 per gallon, which of the following is closest to how much the gas would c

ost for this car to travel 2,727 typical miles? Individual Question $44.44 $109.08 $118.80 $408.04 $444.40

2 answers:

Natasha_Volkova [10]3 years ago

8 0

$408.04 is the answer
hope it helped!

lara [203]3 years ago

4 0

<span>$408.04 is the answers'
hope it helped!</span>

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So percents are just written as 20% = 0.2 so keep that in mind

139 divided by 0.2 is 95 , which would be the price after the discount :)

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2 years ago

A farmer needs to ship 71 pumpkins to a grocery store if each crates can hold 19 pumpkins how many crates Will the farmer need ?

Lesechka [4]

Answer:

The farmer will need 7 crates.

Step-by-step explanation:

<em>It is given that there are 71 pumpkins in total.</em>

<em>And each crate holds 19 pumpkins.</em>

Let the number of crates required be<em> "n".</em>

The total number of pumpkins can be calculated by multiplying number of pumpkins in each crate with total number of crates.

Thus, the equation is

$19(n) = 71$

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2 years ago

In preparation for an earnings report, a large retailer wants to estimate p= the proportion of annual sales

mr Goodwill [35]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, we have a 95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so the critical value is z = 1.96.

The sample size and the estimate are given by:

$n = 161, \pi = \frac{37}{161} = 0.2298$

Hence:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 - 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.1648$

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2298 + 1.96\sqrt{\frac{0.2298(0.7702)}{161}} = 0.2948$

The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).

More can be learned about the z-distribution at brainly.com/question/25890103

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1 year ago