Answer:
a) 21/1240 = 0.017
b) 9/1240 = 7.26*10^-3
c) 3/2480 = 1.21*10^-3
Step-by-step explanation:
There are total 32 M&Ms in the bag
a) Probability that all three are blue M&Ms (without replacement)
(9/32)*(8*31)*(7/30) = 21/1240 = 0.017
b) Probability that the first one selected is blue, the second one selected is orange, and the third one selected is red
(9/32)*(6/31)*(4/30) = 9/1240 = 7.26*10^-3
c) Probability that the first two selected are red, and the third one selected is yellow
(4/32)*(3/31)*(3/30) = 3/2480 = 1.21*10^-3
