Plz help will mark brainlist

What is the slope of the line that passes through the points (2, 3) and (6, 8)?

Nimfa-mama [501]

Answer:

$s = y2 - y1 \div x2 - x1 \\ (8 - 3) \div (6 - 2) \\ 5 \div 4$

5÷4=1.25

7 0

2 years ago

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A triangle has side lengths of 6,8, and 9 what type of triangle is it

Strike441 [17]

9^2 < 6^2 + 8^2

so its acute angled.

5 0

3 years ago

Solve the system of linear equations below. 2x + 3y = 2 x + 6y = 4 x........A.X=0, y =2/3..B..x =2, y = -2/3...C..x=4/3, y=2/9..

Bogdan [553]

I will solve your system by substitution.2x+3y=2;x+6y=4xStep: Solve2x+3y=2for x:2x+3y+−3y=2+−3y(Add -3y to both sides)2x=−3y+22x2=−3y+22(Divide both sides by 2)x=−32y+1Step: Substitute−32y+1forxinx+6y=4x:x+6y=4x−32y+1+6y=4(−32y+1)92y+1=−6y+4(Simplify both sides of the equation)92y+1+6y=−6y+4+6y(Add 6y to both sides)212y+1=4212y+1+−1=4+−1(Add -1 to both sides)212y=3212y212=3212(Divide both sides by 21/2)y=27Step: Substitute27foryinx=−32y+1:x=−32y+1x=−32(27)+1x=47(Simplify both sides of the equation)Answer:x=4/7 and y=2/7
is what i got sorry if it don't help

3 0

4 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

Elena is trying to draw a triangle with side lengths of 4 inches and 3 inches what could be the length of the third side in orde

earnstyle [38]

Elena should put a point where the two circles intersect and draw line segments connecting that point to points A and B to finish her triangle.

4 0

3 years ago