Answer:
(35k + 20) cents
Step-by-step explanation:
First of all, let us have the value of each unit:
1 quarter = 25 cents
1 nickel = 5 cents
1 dime = 10 cents
Given that number of quarter = k
Quarters are 5 lesser than Nickels, so number of nickels = k+5
One more than twice as many dimes as quarters:
k = 2
Number of Dimes + 1
So, number of dimes = ![\frac{1}{2}(k-1)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28k-1%29)
Value of quarters =
cents
Value of nickels = ![5 \times (k+5) = (5k+25)\ cents](https://tex.z-dn.net/?f=5%20%5Ctimes%20%28k%2B5%29%20%3D%20%285k%2B25%29%5C%20cents)
Value of dimes = ![\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28k-1%29%20%5Ctimes%2010%20%3D%20%285k-5%29%5C%20cents)
So, total value of coins =
![25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents](https://tex.z-dn.net/?f=25k%20%2B%205k%20%2B25%20%2B5k-5%5C%5C%5CRightarrow%20%2835k%2B20%29%5C%20cents)
There are two sides (heads and tails). So one head would be 1/2, and one tail would also be 1/2.