Question

Solve the system of linear equations below. 2x + 3y = 2 x + 6y = 4 x........A.X=0, y =2/3..B..x =2, y = -2/3...C..x=4/3, y=2/9...D..x=4, y = -2

Answer 1

I will solve your system by substitution.2x+3y=2;x+6y=4xStep: Solve2x+3y=2for x:2x+3y+−3y=2+−3y(Add -3y to both sides)2x=−3y+22x2=−3y+22(Divide both sides by 2)x=−32y+1Step: Substitute−32y+1forxinx+6y=4x:x+6y=4x−32y+1+6y=4(−32y+1)92y+1=−6y+4(Simplify both sides of the equation)92y+1+6y=−6y+4+6y(Add 6y to both sides)212y+1=4212y+1+−1=4+−1(Add -1 to both sides)212y=3212y212=3212(Divide both sides by 21/2)y=27Step: Substitute27foryinx=−32y+1:x=−32y+1x=−32(27)+1x=47(Simplify both sides of the equation)Answer:x=4/7 and y=2/7 
is what i got sorry if it don't help