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2 years ago

Factor out the greatest common factor. 2s4 - 4s2

Mathematics

1 answer:

mamaluj [8]2 years ago

5 0

Greatest common factor in this case is 2s^2. The resulting polynomial would be 2s^2(s^2-2)

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If the cost of a raffle ticket is $2, which of the following expressions could be used to represent the cost of m tickets? 2m 2

Phantasy [73]

2m would be your answer

Each ticket costs $2, which means that if you are buying more tickets, it would look like: 2 + 2.... instead of the others

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3 years ago

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Stells [14]

Answer:

The second and fourth option

Step-by-step explanation:

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2 years ago

Dillon has 4 blue marbles and 3 times as many red marbles.Max has 8 times as many red marbles as Dillon.How much red marbles do

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2 years ago

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Alenkinab [10]

Answer:

$15x-6y=48$

Step-by-step explanation:

So we have the system of equations:

$5x-2y=16\\15x-7y=51$

And we want to multiply the first equation by some constant such that the resulting equation matches the coefficient of [x] in the second equation.

We can see that the coefficient of x in the second equation is 15.

So, to match 15, we must multiply the first equation by 3. So:

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2 years ago

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Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).

Natalija [7]

Answer:

9a^4 b^10(2 +3a^6 b^5) (2 -3a^6 b^5)

see work below

Step-by-step explanation:

36a^4b^10 - 81a^16b^20

A) find the GCF

36a^4b^10 = 4*9 a^4b^10 = 2*2*3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b

81a^16b^20= 9*9a^16b^20= 3*3*3*3* a*a*a*a*a*a*a*a*a*a*a*a*a*a*a*a *b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b*b

The terms that appear in both terms is the GCF. The terms that remain are inside the parentheses.

The GCF is 3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b

36a^4b^10 - 81a^16b^20 = 3*3 a*a*a*a*b*b*b*b*b*b*b*b*b*b *

( 2*2 - 3*3a*a*a*a*a*a*a*a*a*a*a*a b*b*b*b*b*b*b*b*b*b)

Combining like terms

36a^4b^10 - 81a^16b^20 = 9a^4b^10(4-9a^12b^10)

The expression inside the parenthesis can be factored using the difference of squares

let x^2 =4 x =2

y^2 = 9a^12 b^10 y = 3a^6b^5

(x^2 -y^2) = (x+y)(x-y)

9a^4b^10(4-9a^12b^10) = 9a^4b^10 ( 2+3a^6b^5) ( 2-3a^6b^5)

b) difference of squares a^2 – b^2 = (a + b)(a – b)

let a^2 = 36a^4b^10

so a = 6a^2b^5

b^2 = 81a^16b^20

b = 9a^8 b^10

a^2 – b^2 = (a + b)(a – b)

36a^4b^10 - 81a^16b^20 = (6a^2b^5 +9a^8 b^10) (6a^2b^5 -9a^8 b^10)

We can factor a 3 a^2 b^5 out of the first term

3 a^2 b^5 (2 +3a^6 b^5) (6a^2b^5 -9a^8 b^10)

3 a^2 b^5 (2 +3a^6 b^5) 3 a^2 b^5 (2 -3a^6 b^5)

Multiply the terms outside the parentheses together

9a^4 b^10(2 +3a^6 b^5) (2 -3a^6 b^5)

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2 years ago

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