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Alina [70]
3 years ago
12

Evaluate the given expression for x = 3 and y = 2.

Mathematics
1 answer:
kumpel [21]3 years ago
4 0

Answer:

11

Step-by-step explanation:

3(2) - (3(3) + 2) + 16

6 - (9 + 2) + 16

6 - 11 + 16

11

<em>good luck, hope this helps :)</em>

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What is 15 minutes before 4:35? what time would that be? pls answer today!!!
Andrews [41]

Answer:

4:20

Step-by-step explanation:

35-15= 20

7 0
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i a man even number beetween 50 and 99 i am a multiple of 9 my tens digit is 5 more than my units digit
vodomira [7]
Hello,
multiple of 9 betheen 50 and 99 are :54,63,72,81,99
and 54,72  are even.
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6 0
3 years ago
Which figure represents the image of parallelogram
Xelga [282]

Answer:

correct choice is option 3 - figure C.

Step-by-step explanation:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. This gives you such reflection rule:

From the diagram:

L(3,1), M(4,3), N(5,3) and P(4,1).

Using the reflection rule, you can find coordinates of image points:

L'(1,3), M'(3,4), N'(3,5) and P'(1,4).

As you can see, these are coordinates of vertices of the figure C.

<em>on e2020 its c </em>

<em>give brainliest if this helps please (;</em>

4 0
4 years ago
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*EXTRA PTS* answer these pls :)
Aneli [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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I Need to find the Function Operations​
Alinara [238K]

Answer:

1) (f+g)(x)=2x^2+3x-6

2) (f-g)(x)=2x^2+x

3) (f \cdot g)(x)=2x^3-4x^2-9x+9

Step-by-step explanation:

So we have the two functions:

f(x)=2x^2+2x-3\text{ and } g(x)=x-3

And we want to find (f+g)(x), (f-g)(x), and (f*g)(x).

1)

(f+g)(x) is the same to f(x)+g(x). Substitute:

(f+g)(x)=f(x)+g(x)\\=(2x^2+2x-3)+(x-3)

Combine like terms:

=(2x^2)+(2x+x)+(-3-3)

Add:

=2x^2+3x-6

So:

(f+g)(x)=2x^2+3x-6

2)

(f-g)(x) is the same to f(x)-g(x). So:

(f-g)(x)=f(x)-g(x)\\=(2x^2+2x-3)-(x-3)

Distribute:

=(2x^2+2x-3)+(-x+3)

Combine like terms:

=(2x^2)+(2x-x)+(-3+3)

Simplify:

=2x^2+x

So:

(f-g)(x)=2x^2+x

3)

(f*g)(x) is the same to f(x)*g(x). Thus:

(f\cdot g)(x)=f(x)\cdot g(x)\\=(2x^2+2x-3)(x-3)

Distribute:

=(2x^2+2x-3)(x)+(2x^2+2x-3)(-3)

Distribute:

=(2x^3+2x^2-3x)+(-6x^2-6x+9)

Combine like terms:

=(2x^3)+(2x^2-6x^2)+(-3x-6x)+(9)

Simplify:

=2x^3-4x^2-9x+9

So:

(f \cdot g)(x)=2x^3-4x^2-9x+9

4 0
3 years ago
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