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VikaD [51]
4 years ago
11

What is the mass number of an ion with 106 electrons, 158 neutrons, and a +1 charge?

Chemistry
2 answers:
Effectus [21]4 years ago
5 0
The mass number would be 265
sergey [27]4 years ago
5 0

Answer:

The correct answer is 265.

Explanation:

Hello!

Let's solve this!

In the nucleus there will be 158 neutrons and as we know that in the atom there is the same amount of protons as there are electrons, there would be 106. But it says that it has a +1 charge with which we have 107 protons.

The mass of the atom will be 107 + 158 = 265.

We conclude that the correct answer is 265.

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Which element is classified as an alkali metal?
dusya [7]

Explanation:

All the elements of group 1 in the periodic table are known as alkali metals. These are lithium (Li), sodium (Na), potassium (K), rubidium (Rb), caesium (Cs), and francium (fr).

Characteristics of alkali metals are as follows.

  • Alkali metals are soft and can be cut with a knife.
  • They are good conductors of heat and electricity.
  • They have only 1 electron in their outermost sub-shell.
  • They are very reactive.
  • Alkali metals are ionic in nature.
3 0
3 years ago
Read 2 more answers
Name:_____________________________________________________ Date:___________ Period:_________ 3/23 - 3/27 Assignment 1: Gas Law P
crimeas [40]

Answer:

The answers are;

1. 8.2 liters

2. 1214.84 ml

3. 318.027 K

4. 4.00 l.

Explanation:

1. Boyle's law states that the volume of  given mass of gas is inversely proportional to its pressure at constant temperature

that is

P₁·V₁ = P₂·V₂

Where:

P₁ = Initial pressure = 40.0 mm Hg

V₁ = Initial volume = 12.3 liters

P₂ = Final pressure = 60.0 mm Hg

V₂ = Final volume = Required

From P₁·V₁ = P₂·V₂, V₂ is given by

V_2=\frac{P_1\cdot V_1}{P_2} = \frac{40.0 mm Hg\cdot 12.3 l}{60.0 mm Hg} =  8.2 l

The volume reduces to V₂ = 8.2 liters

2. Here Charles law states that

\frac{T_1}{V_1} =\frac{T_2}{V_2}

T₁ = Initial temperature = 27.0 °C = 300.15 K

V₁ = Initial volume = 900.0 mL

T₂ = Final temperature = 132.0 °C = 405.15 K

V₂ = Final volume = Required

Therefore  V_2 =\frac{T_2\cdot V_1}{T_1} = \frac{405.15 K\times 900.0 mL}{300.15 K} = 1214.84 ml

V₂ = 1214.84 ml

3.  Gay-Lussac's Law states that

\frac{T_1}{P_1} =\frac{T_2}{P_2}

Where:

P₁ = Initial pressure = 15.0 atmospheres

T₁ = Initial temperature = 25.0 °C = 298.15 K

P₂ = Final pressure = 16.0 atmospheres

T₂ = Final temperature = Required

∴ T_2 = \frac{T_1\times P_2}{P_1}

=  \frac{298.15 K\times 16.0atm}{15.0atm} = 318.027 K

T₂ = 318.027 K

4. Avogadro's law states that,

Equal volume of all gases at the same temperature and pressure contain equal number of molecules.

Therefore if 5.00 moles of gas occupies 2.00 l volume, then

1 moles will occupy 2.00/5 l volume and

10 moles will occupy 2.00/5 × 10 or 4.00 l volume.

6 0
4 years ago
A substance with a ph of 9 has
Arisa [49]

Answer:

c) more OH⁻ ions than H₃O⁺ ions

Explanation:

A substance with a PH of 9 implies that it has more OH⁻ ions than H₃O⁺ ions.

Such substances are said to be an alkaline or a base.

A base is a substance the produces excess hydroxyl ion in aqueous solutions.

An acid will produce excess hydroxonium ions in a solution.

So, the pH scale is used to indicate whether a substance is an acid or base or non of them.

Acids have pH of less than 7

Bases have pH of > 7

4 0
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<em>Mass</em><em>=</em><em>5</em><em>0</em><em>0</em><em>g</em><em> </em><em>=</em><em>5</em><em>0</em><em>0</em><em>/</em><em>1000</em><em>=</em><em>0</em><em>.</em><em>5</em><em> </em><em>kg</em>

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<em>Now</em><em>,</em>

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5 0
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Calculate the mass in grams for a single molecule of carbon monoxide​
Oxana [17]

Answer:

7.307 x 10^-23

Explanation:

mass of one molecule = mr/ avogadros number

= 44/6.022 x 10^23

= 7.307x 10^-23

4 0
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