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Scrat [10]
3 years ago
12

Will all random samples from a given population have the same mean? Provide an explanation with your answer.

Mathematics
2 answers:
avanturin [10]3 years ago
5 0

Short answer No.


Explanation

Suppose you have a sample of coins that have the date of production on them. They go from 1990 to 2000 inclusive. There are 100 coins in each year. That means there are 1100 coins because there are 11 years. Now you pick out 10 coins without replacement. Let's say all of them are from 1999. Then the mean is 1999.


If you start again and pick out 10 and get 3 years

4 from 2000

2 from 1995

4 from 1992


Whatever the mean is, it is not 1999. The mean of the second batch is 1995.8!

Tpy6a [65]3 years ago
5 0

Answer:

Data from random samples will not always include the same values. Values are chosen randomly and they may or may not be the same. So means will vary among samples.

Step-by-step explanation:

Even though the data comes from the same population, different values are chosen with each sample.

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In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t 2 , 2 + t − 5t 2 , 1 + 2t} to the standard basis of P2.
Serjik [45]

Complete Question:

In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.

Answer:

The change of coordinate matrix is :

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

Step-by-step explanation:

Let U =  {D, E, F} be any vector with respect to Basis B

U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)

U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)

In Matrix form;

\left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right] \left[\begin{array}{ccc}D\\E\\F\end{array}\right] = \left[\begin{array}{ccc}D+2E+F\\E+2F\\-3D-5E\end{array}\right]

The change of coordinate matrix is therefore,

M = \left[\begin{array}{ccc}1&2&1\\0&1&2\\-3&-5&0\end{array}\right]

To find D, E, F in (**) such that U = t²

D + 2E + F = 0.................(1)

E + 2F = 0.........................(2)

-3D -5E = 1........................(3)

Substituting eqn (2) into eqn (1 )

D=3F...................................(4)

Substituting equations (2) and (4) into eqn (3)

-9F+10F=1

F = 1

Put the value of F into equations (2) and (4)

E = -2(1) = -2

D = 3(1) = 3

Substituting the values of D, E, and F into (*)

U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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