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vladimir2022 [97]
3 years ago
7

Due tomorrow please help :)

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0
Okay, so your first one, number six. You have two shapes there, a cone and a circle. Now you have a full cone and a half of a circle. Let's start with the cone. The formula for the volume of a cone is πr²h/3. You have your height, that is 12, so get your paper out and plug that in. H = 12. Now, your radius is where it gets a bit tricky. Have you ever heard of the Pythagorean theorem? It's a²+b²=c². Look at the cone, but look at it like it's a two-dimensional shape. You see the triangle in the middle, ignore the rest and pretend it's only that triangle. You now have a right triangle, You know your height is 12, and by looking at the triangle adjacent to it, and know it's equal, you know that your hypotenuse (the longest side of your triangle) is 15. So plug that into the Pythagorean theorem. Now you have 12²+b²=15². Use algebra to work that out, and you're left with 9. So your radius is 9. Now plug that into your volume of a cone equation. The volume of the cone is about 1017.88. Now find the circle or sphere. The formula is 4/3πr³. Just plug in your radius and get your answer, which is 3053.63. Now cut that in half, as you've only got half a circle. Now you've got 1526.82. Now add that to the volume of your cone, and you've got your final answer. 2544.7, or about that. I used π on a calc, and not 3.14, so it might be a little different.

Do you think you can do the next one? Just look at your triangle in there. You've already got one side and a hypotenuse, so plug it into the Pythagorean theorem and get your last side. Then look at the little marks on there and you can see if places are the same. If you need help with it don't hesitate to ask. I'm staying up all night anyway. Homeschooled and behind, so I'm not going anywhere.
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Im trying to procrastinate so if you would please help me speed up th process. I have like 20 minutes
Katarina [22]

Answer:

1/3=0.33 barred(the threes go on infinitly)

1/6=16666 barred(the sixes go on infinitly)

1/6 as a percent is 16.66% barred(the sixes go on infinitly)

Hope This Helps!!!

7 0
3 years ago
Read 2 more answers
Find the a value, b value, and c value.​
Naddik [55]

Answer:

aX²+bX+c=0

a=1

b=-8

c=12

3 0
3 years ago
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If f(x) = 5x(3exponent) - 2 and g(x) = 2x+1 , find (f+g) (x)
Rus_ich [418]

For this case we must find

(f + g) (x).

By definition we have to:

(f + g) (x) = f (x) + g (x)

We have the following functions:

f (x) = 5x ^ 3-2\\g (x) = 2x + 1

Now, applying the given definition, we have:

(f + g) (x) = 5x ^ 3-2 + 2x + 1\\(f + g) (x) = 5x ^ 3 + 2x-1

Answer:

(f + g) (x) = 5x ^ 3 + 2x-1

4 0
3 years ago
Find the sum of the equation
stealth61 [152]

Answer:

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

Step-by-step explanation:

1)  Rewrite {y}^{2}-2y+1y  in the form{a}^{2}-2ab+{b}^{2}, where a = y and b = 1.

\frac{y}{{y}^{2}-2(y)(1)+{1}^{2}}+\frac{6}{{y}^{2}+6y-7}

2)  Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}.

\frac{y}{{(y-1)}^{2}}+\frac{6}{{y}^{2}+6y-7}

3)  Factor {y}^{2}+6y-7.

1 - Ask: Which two numbers add up to 6 and multiply to -7?

-1 and 7

2 - Rewrite the expression using the above.

(y-1)(y-7)

Outcome/Result: \frac{y}{(y-1)^2} +\frac{6}{(y-1)(y+7)}

4) Rewrite the expression with a common denominator.

\frac{y(y+7)+6(y-1)}{{(y-1)}^{2}(y+7)}

5)  Expand.

\frac{{y}^{2}+7y+6y-6}{{(y-1)}^{2}(y+7)}

6) Collect like terms.

\frac{{y}^{2}+(7y+6y)-6}{{(y-1)}^{2}(y+7)}

7) Simplify  {y}^{2}+(7y+6y)-6y  to  {y}^{2}+13y-6y

\frac{{y}^{2}+13y-6}{{(y-1)}^{2}(y+7)}

5 0
2 years ago
Read 2 more answers
There are 60 elm trees in the park. This amount represents 40% of the trees in the park. How many trees are in the park?
slamgirl [31]
60 is 40% of total trees.

total trees = 60 * 100/40 = 150

Answer is D.
4 0
3 years ago
Read 2 more answers
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