The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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21/10 divided by 2 4/5 represents the time spent on a shift
<h3>How to determine what 21/10 divided by 2 4/5 represent in this situation?</h3>
The given parameters are
Time = 21/10
Shifts = 2 4/5
This means that:
21/10 divided by 2 4/5 represents:
Time/Shift
i.e. time per shift
Hence, 21/10 divided by 2 4/5 represents the time spent on a shift
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3 buckets covers 90m x 80cm = 3 buckets for 90x0.8 = 3 for 72
x buckets covers 200m x 120cm = x buckets for 200x1.2 = x for 240
3/72 = x/240
720 = 72x
x =10 buckets of paint to cover 200mx120cm fence