Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
Rate of burn(scented):1/8inch in 1/4h
=4(1/8)inch in 1h=1/2inch in 1h
Rate of burn(unscented):1/9inch in 1/3h=3(1/9)inch in 1h=1/3inch in 1h
The scented candle burns more in one hour.
1/2inch-1/3inch=1/6inch
The scented candle burns 1/6inch more per hour
The GCF of 24, 32, and 80 must be 8, since it is the largest number common to both lists. Example 1 Find the greatest common factor of each set of numbers by listing factors.
Answer:
y = 
x + 7
Step-by-step explanation:
the equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b ) a point on the line
y - 8 = - 
(x + 5) ← is in point- slope form
with m = -
given a line with slope m then the slope of a line perpendicular to it is
= - 
= - 
=
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept ) , then
y = x + c ← is the partial equation
to find c substitute (- 6, - 2 ) into the partial equation
- 2 = - 9 + c ⇒ c = - 2 + 9 = 7
y = x + 7 ← equation of line K
2 | 10500
2 ! 5250
3 | 2625
5 | 875
5 | 175
5 | 35
7
The prime factors are 2*2*3*5*5*5*7 or 2^2*3*5^3*7
