Ask question

Ask question

All categories

3 years ago

5

The forth term of an arithmetic seaquence is 19 and the fifth term is 13 . what is the third term

1 answer:

Vaselesa [24]3 years ago

5 0

The third term was likely to be 25. You can see a pattern -6 when it goes up a term.

You might be interested in

Malachi bought a new fishing rod. The regular price of the fishing rod was $125.99. Sales tax of 8% is applied(added) to the tot

madreJ [45]

Answer:

125.99/100 X 108 = 136.0692

round to 2 dp = $136.07

5 0

3 years ago

Eric randomly surveyed 150 adults from a certain city and asked which team in a contest they were rooting for, either North Hig

Romashka-Z-Leto [24]

Answer:

B

Step-by-step explanation:

A 95% confidence level interval will have 0.52 (lower interval) & 0.68 (upper interval) which means that that if 90 individuals root for North HS then p value is 0.6 which will fall in the 95% confidence interval range.
For the option B the p value will also be same as in case A hence B is true as an alternative hypothesis.
We can calculate P value

Confidence Interval = p ± z $\sqrt{p(1-p)/n}$

4 0

3 years ago

Which of the following polynomials is the expansion of (x - y)4? x4 - x3y + x2y2 - 2xy3 + y4 x4 -2x3y3 + y4 x4 - 2x3y + x 2y 2 -

sammy [17]

Answer:

$(x-y)^4=x^4-x^3y+6x^2y^2-4xy^3+y^4$ .

Step-by-step explanation:

We want to find the polynomial that will result from expanding:

$(x-y)^4$ .

Recall that we can use the Pascal's triangle to obtain the coefficient as:

1 4 6 4 1

Also note how the negative sign is going to alternate.

The <em>power of x </em>will decrease from left to right while the <em>power of y</em> increases from left to right

The expansion then becomes:

$(x-y)^4=x^4-x^3y+6x^2y^2-4xy^3+y^4$ .

7 0

3 years ago

What shortcut would you use to prove the<br> triangles congruent?

professor190 [17]

ASA but I’m not sure

3 0

3 years ago

A bicycle training wheel has a radius of 3 inches. The bicycle wheel has a radius of 10 inches. Approximately how much smaller,

zhuklara [117]

Answer:

$285.74\text{ inch}^2$

Step-by-step explanation:

GIVEN: A bicycle training wheel has a radius of $3\text{ inch}$ . The bicycle wheel has a radius of $10\text{ inch}$ .

TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.

SOLUTION:

radius of bicycle wheel $=10\text{ inch}$

area of bicycle wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times10^2$

$=314\text{ inch}^2$

radius of bicycle training wheel $=3\text{ inch}$

area of bicycle training wheel $=\pi r^2$

putting value,

area of bicycle wheel $=3.14\times3^2$

$=28.26\text{ inch}^2$

difference in area of bicycle wheel and bicycle training wheel

$=\text{area of bicycle wheel}-\text{area of bicycle training wheel}$

$=314-28.26$

$=285.74\text{ inch}^2$

hence the training wheel is $285.74\text{ inch}^2$ smaller than regular wheel

4 0

3 years ago