Prove that there is only one circle determined by three noncollinear points
2 answers:
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Answer:
= 130°
Step-by-step explanation:
Angles subtended at the center by the arcs and
are ∠HPG and ∠EPF.
Since these angles are the vertical angles both will be equal.
m∠HPG ≅ m∠EPF
3x - 10 = 2x + 10
3x - 2x = 10 + 10
x = 20
Therefore,
= 50°
Similarly = 50°
In the same way angles subtended at the center will be equal.
m∠EPH ≅ m∠FPG
and
Since °
Therefore, measure of arc EH = 130°