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____ [38]
3 years ago
6

Please help thnk you.

Mathematics
2 answers:
kap26 [50]3 years ago
8 0
Hey there! :D

Find the scale by using a proportion. 

\frac{18}{27} =  \frac{6}{x}

Cross multiply. 

x*18= 6*27

x*18= 162

Divide both sides by 18. 

x= 9

"C" or 9 is your answer.

I hope this helps!
~kaikers


Levart [38]3 years ago
7 0
Hello!

You have to find what they multiplied to 18 to get 27

27 / 18 = 1.5

The multiplied the sides by 1.5 to get the second shape

6 * 1.5 = 9

The answer is C)9

Hope this helps!
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Resolver el siguiente sistema de ecuación:
snow_tiger [21]

Answer:

x=-1\\y=4

Step-by-step explanation:

\frac{5x+2y}{3}=1

\frac{2x+y}{2}=1

Vamos a utilizar el método de sustitución. Vamos a despejar la segunda ecuación por alguna de las variables. Elegiré la y porque esta sola.

\frac{2x+y}{2}=1

Vamos a empezar por eliminar ese 2 del denominador. Para hacer esto, multiplicamos por 2 ambos lados de la ecuación.

2x+y=1*2

2x+y=2

Como vamos a despejar la y, restamos 2x en ambos lados.

y=2-2x

Listo.

------------------------------------------------------------------------

Procedemos a reemplazar el valor de y en la primera ecuación.

\frac{5x+2y}{3}=1

\frac{5x+2(2-2x)}{3}=1

\frac{5x+4-4x}{3} =1

Procedemos a operar términos semejantes.

\frac{x+4}{3} =1

Nos deshacemos del 3 multiplicando.

x+4=1*3\\x+4=3

Restamos 4

x=3-4\\x=-1

-----------------------------------------------------------------------------

Una vez encontrado el valor de x, procedemos a reemplazar en cualquier ecuación para encontrar el valor de y. Usaré la segunda ecuación.

\frac{2x+y}{2}=1

\frac{2(-1)+y}{2}=1

Procedemos a resolver;

\frac{-2+y}{2} =1

Multiplicamos por 2.

-2+y=1*2

-2+y=2

Sumamos 2

y=2+2\\y=4

-------------------------------------------------------------------------------

Para comprobar que los valores son correctos, reemplazamos ambos valores en cualquier ecuación y el resultado debe ser igual.

Usaré la primera.

\frac{5x+2y}{3} =1

\frac{5(-1)+2(4)}{3} =1

Resolvemos;

\frac{-5+8}{3} =1

\frac{3}{3}=1

1=1

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