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Mekhanik [1.2K]
3 years ago
10

What % of 400 = 193

Mathematics
1 answer:
saveliy_v [14]3 years ago
3 0
The best way to find your answer is to divide 193 by 400 to get .4825 and to make sure if it is the answer you take 400 and multiply .4825 and it will be 193 so .4825 = 48.25%
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3 years ago
Find the period of the function
Ostrovityanka [42]

Answer:

6π

Step-by-step explanation:

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You divide 2π by the factor in front of your function variable. This is 1/3 for your function.

So 2π/(1/3) = 6π

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Step-by-step explanation:

Remember,

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3 0
3 years ago
What to the third power is equal to 729
atroni [7]

If you had absolutely no idea, then you'd have roughly two choices
of how to find it:

#1).  Try numbers until you find the right one.

        Pick a number.
        Cube it.
        If you get less than 729, go back and try a bigger number.
        If you get more than 729, go back and try a smaller number.
        Eventually you find the right one.  

Try 1.        1³ = 1 .            Too small.
Try 2.        2³ = 8 .            Still too small.
Try 5.        5³ = 125 .        Still too small.
Try 20.     20³ = 8,000.      Ooops.  Too big.
Try 10.     10³ = 1,000       Too big.
Try 8.         8³ = 512.         Oooo.  Too small, but maybe getting close.
Try 8.5.    8.5³ = 614.125   Still too small, but very close.
Try 9.         9³ = 729 .       That's it !            yay !


#2).  x³ = 729

Take the log of each side:      log(x³) = log(729)

                                         3 log(x)  =  log(729)

Divide each side by  3 :         log (x)  =  (1/3) log(729)

Look up log(729) :                 log(x)  =  (1/3) (2.86272...)

                                                      =    0.95424...
Raise 10 to the power
of each side:                      10^log(x)  =  10⁰·⁹⁵⁴²⁴···  

                                               x        =  8.99994...

                                         (That's the way it is with logs.
                                          They never come out even.)
5 0
3 years ago
Read 2 more answers
The length of a rectangle is twice its width. if the area of the rectangle is 162 m2 , find its perimeter.
polet [3.4K]
L = 2W
A = L * W
A = 162

162 = 2W(W)
162 = 2W^2
162/2 = W^2
81 = W^2
sqrt 81 = W
9 = W

L = 2W
L = 2(9)
L = 18

P = 2(L + W)
P = 2(18 + 9)
P = 2(27)
P = 54 <===== perimeter is 54 m
6 0
3 years ago
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