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masha68 [24]
3 years ago
5

The members of a cooking club are making cakes, which they will sell at a street fair for $14 apiece. It cost $22 for a booth at

the fair, and the ingredients for each cake cost $3. At some point, the club members will sell enough cakes so that their sales cover their expenditures. How much will the sales and expenditures be? How many cakes will they have sold?
Mathematics
1 answer:
tangare [24]3 years ago
8 0
Is the amount of cakes estimated or rounded??
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The population of algae in an experiment has been increasing by 5% each day. If there were 5p algae at the beginning of the expe
Ostrovityanka [42]

Answer:

Number of algae in 7 days = 70.355

Step-by-step explanation:

Given:

Algae in beginning = 50

Rate of increasing = 5% per day = 0.05

Number of days = 7 days

Find:

Number of algae in 7 days.

Computation:

Number\ of\ algae\ in\ 7\ days = Algae\ in\ beginning(1+Rate\ of\ increasing)^{Number\ of\ days}\\\\Number\ of\ algae\ in\ 7\ days = 50(1+0.05)^7\\\\Number\ of\ algae\ in\ 7\ days = 70.355

Number of algae in 7 days = 70.355

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3 years ago
What is the property of -8+3 = 3+ (-8)
Marizza181 [45]

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12

Step-by-step explanation:

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3 years ago
Can someone please help me out here?
fenix001 [56]
1. D
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Answer:

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A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0
4 years ago
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