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Lorico [155]
3 years ago
14

Calculate cos theta to two decimal places. A. 0.69 B. 1.38 C. -0.07 D. 0.77

Mathematics
2 answers:
77julia77 [94]3 years ago
8 0

Answer:

A. 0.69

Step-by-step explanation:

Using the cosine law

a² = b² + c² - 2bc cos A

b² = a² + c² - 2ac cos B

c² = a² + b² - 2ab cos C

8² = 7² + 11² - 2 × 7× 11 cos ∅

64 = 49 + 121 -154 × cos ∅

64 = 170 - 154 cos ∅

64 - 170 = -154 cos ∅

- 106 = -154 cos ∅

cos ∅ = -106/-154

cos ∅ = 0.6883116883 ≈ 0.69

alexgriva [62]3 years ago
4 0

Answer:

A. 0.69

Step-by-step explanation:

We need to use cosine theorem:

c²=a²+b² - 2ab* cos(θ)

c=8, a=7, b=11

8² = 7²+11² - 2*7*11 *cos(θ)

64 = 49 + 121 - 154*cos(θ)

64 - 170 = - 154*cos(θ)

- 106/ (- 154) = cos(θ)

cos(θ) = 0.69

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4 years ago
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Find acute angle between the line 2x+4y=7 and x+2y=5
Morgarella [4.7K]

Answer:

arctan(4/3) ≈ 0.9272

Step-by-step explanation:

On comparing eqⁿ to y = mx + c,

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Therefore, if A is the angle b/w them,

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3 years ago
After seeing many commercials claiming you can get cheaper car insurance from an online company, a local insurance agent decides
Gemiola [76]

Answer:

t=\frac{-34.90-0}{\frac{95.66}{\sqrt{10}}}=-1.154    

The degrees of freedom are:

df = n-1= 10-1=9

The p value would be given by:

p_v =P(t_{9}

The p value is a large value and if we use a significance level of 0.05 or 0.1 we see that we can FAIL to reject the null hypothesis. And then we don't have enough evidence to conclude that her clients would save money on average by switching to the online company

Step-by-step explanation:

Information given

\bar X=-34.90 represent the mean for the difference

s=95.66 represent the sample deviation for the difference

n=10 sample size    

\mu_o =0 represent the value that we want to test  

\alpha represent the significance level

t would represent the statistic

p_v represent the p value

System of hypothesis

We want to determine if that her clients would save money on average by switching to the online company, the system of hypothesis would be:    

Null hypothesis:\mu \geq 0    

Alternative hypothesis:\mu < 0    

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

Replacing the info given we got:

t=\frac{-34.90-0}{\frac{95.66}{\sqrt{10}}}=-1.154    

The degrees of freedom are:

df = n-1= 10-1=9

The p value would be given by:

p_v =P(t_{9}

The p value is a large value and if we use a significance level of 0.05 or 0.1 we see that we can FAIL to reject the null hypothesis. And then we don't have enough evidence to conclude that her clients would save money on average by switching to the online company

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3 years ago
Read 2 more answers
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