Answer: I believe the answer is A. The order of amino acids in the protein.
Explanation:
Answer:
See explanation
Explanation:
The elements in group form univalent positive ions and element in group 17 form univalent negative ions. Hence, when a group 1 element reacts with a group 17 element, a compound of the sort MX is formed. Hence, when a group 1 element reacts with bromine, a salt is formed with the general formula MBr.
Elements of group 1 are highly electro positive metals. They react with water to form the metal hydroxide and release hydrogen gas. Hence, when group 1 elements react with water, hydrogen gas is released.
A group 1 element forms a univalent positive ion while a group 16 element forms a divalent negative ion. Hence, when a groups 1 element reacts with oxygen, the compound formed must have the general formula M2O.
The reactivity of group 1 metal increases down the group hence Cs is the most reactive group 1 element.
Lithium displays a slightly different chemistry from other group 1 elements because of its small size.
Answer:
See explanation
Explanation:
Molar mass of NaCl = 58.5 g
Number of moles contained in 10 g of NaCl = 10 g/58.5 g = 0.17 moles
If 1 mole of NaCl contains 6.02 * 10^23 atoms
0.17 moles of NaCl contains 0.17 * 6.02 * 10^23 atoms = 1.02 * 10^23 atoms
Molar mass of Fe II chloride = 126.751 g/mol
Number of moles = 10 g/126.751 g/mol = 0.0789 moles
Number of atoms = 0.0789 moles * 6.02 * 10^23 atoms = 4.7 * 10^22 atoms
Molar mass of Na = 23 g/mol
Number of moles = 10g/23 g/mol = 0.43 moles
Number of atoms = 0.43 moles * 6.02 * 10^23 atoms = 2.59 * 10^ 23 atoms
Answer is: less acetic acid to neutralize it.
Balanced chemical reaction of sodium bicarbonate solution and acetic acid: NaHCO₃(aq) + CH₃COOH(aq) → CH₃COONa(aq) + H₂O(l) + CO₂(g).
According to chemical reaction: n(NaHCO₃) : n(CH₃COOH) = 1 : 1.
Stronger solution of sodium bicarbonate (NaHCO₃), more acetic acid (CH₃COOH) is neeed for neutralization.
Answer:
11.55 mol ≈ 11.6 mol CO2
Explanation:
C3H8 (g) + 5O2(g) → 3CO2 (g) + 4H2O(g)
from reaction 1 mol 3 mol
given 3.85 mol x mol
Solving proportion
x =(3.85*3)/1 = 11.55 mol ≈11.6 mol
