While the normal gas flame can
only produce a “operating” to “light blue” type of flame, the Bunsen burner can
at least yield three types of flame. Consequently, the following: <span><span />
Operating flame
– which is yellow/orange in color, near 300° C. </span>
<span><span>·
</span>
Blue flame –
can be imperceptible under normal lighting conditions, near 500° C. The typically
used laboratory type of flame.</span>
<span><span>·
</span>Roaring-blue
flame – forms a triangular shaped in the center of the flame normally light
blue in color and interestingly, it’s a sound-producing flame. Heat is near to
700° C. </span>
Imagine with this three kinds
of flame produced and a Bunsen burner creates compared to a simple normal gas
flame. In sense, the roaring-blue flame proves evident as to why Bunsen burner
is hotter hence, the amount of heat it makes (700°C) it makes.
Answer:
6.9 g
Step-by-step explanation:
1. Use the Ideal Gas Law to find the <em>number of moles
</em>
pV = nRT Divide each side by RT
n = (pV)/(RT)
<em>Data:
</em>
p = 102 kPa
V = 6.0 L
R = 8.314 kPa·L·K⁻¹mol⁻¹
T = (37 + 273.15) K = 310.15 K
<em>Calculation:
</em>
n = (102 × 6.0)/(8.314 × 310.15)
n = 0.237 mol
2. Calculate the <em>mass of air
</em>
Mass of air = 0.237 mol × (29 g/1 mol)
Mass of air = 6.9 g
Answer:
0001 M HCl is the same as saying that 1 *10-4 moles of H+ ions have been added to solution. The -log[. 0001] =4, so the pH of the solution =4
